All categories

3 years ago

(23 PTS) WILL GIVE BRAINLIST

Mathematics

1 answer:

Effectus [21]3 years ago

4 0

Answer:

Step-by-step explanation:

g(x) would be

- 2

You might be interested in

Oncepts in Probability and Statistics - MA3120 A-CR-2021010

shepuryov [24]

Answer:

I see..

Step-by-step explanation:

so u do thishfbdjdid

4 0

3 years ago

Joey has two pieces of wood. One is 120 inches and the other one is 210 inches long. He wants to cut both the pieces into smalle

deff fn [24]

Answer:

A. 30 inches

B. 11 pieces

Step-by-step explanation:

Piece 1 = 120 inches

Piece 2 = 210 inches

1. He wants the smallest pieces to be as long as possible without having any leftover, how long should each piece be?

Find the highest common factor of 120 and 210

120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, and 120.

210: 1, 2, 3, 5, 6, 7, 10, 14, 15, 21, 30, 35, 42, 70, 105, 210.

The highest common factor of 120 and 210 = 30

Therefore, the smallest and longest pieces should be cut into 30 inches each

B. Total Smaller pieces of wood = piece 1 / 30 + piece 2 / 30

= 120/30 + 210/30

= 4 + 7

= 11 pieces

4 0

3 years ago

What is 2/5+1/2? i am very stressed out, and i need an answer. plz someone help!

VashaNatasha [74]

2/5 + 1/2 =

4/10 + 5/10 =

9/10

hope dis helps boi

4 0

4 years ago

Help please Algebra 2 B

bonufazy [111]

A1 = 2/5, an = an-1 * 5

8 0

3 years ago

Find sin4a and cos4α, if tanα=3

Mashcka [7]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

Sin2α = 2SinαCosα.

Cos2α = (Cosα)^2 - (Sinα)^2.

Sin4α can be written as Sin2(2α).

Similarly Cos4α can be written as Cos2(2α).

$Sin 4\alpha = 2Sin 2\alpha \times Cos 2\alpha = 2Sin 2\alpha \times(Cos^{2} \alpha - Sin^{2} \alpha ) = 4Sin \alpha \times Cos \alpha \times (Cos^{2} \alpha - Sin^{2} \alpha )$

It is given that tanα=3.

Sinα(Sinα) = $\frac{9}{10}$ [ $Sec^{2} \alpha = 1 + 3^{2} = 10.\\Cos^{2} \alpha = \frac{1}{10} \\Sin^{2} \alpha = 1 - \frac{1}{10} = \frac{9}{10}$ ], the values either be both positive or both negative, as the value of tanα is positive only on first and third quadrant.

Sin4α = $4\times \sqrt{(\frac{9}{10} )} \times \sqrt{(\frac{1}{10} )} \times (\frac{1 - 9}{10} ) = -\frac{4\times8\times3}{100} = -\frac{96}{100}$ .

Cos4α = $Cos^{2} 2\alpha - Sin^{2} 2\alpha = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - Sin^2 {2\alpha } = (Cos^{2} \alpha - Sin^{2} \alpha )^{2} - (2Sin \alpha Cos \alpha )^{2} = (-\frac{8}{10} )^{2} - \frac{4\times9}{100} = \frac{64 - 36}{100} = \frac{28}{100} = \frac{7}{25}$

7 0

3 years ago