3 years ago

Cuanto es dcneicneen eie neim

Mathematics

2 answers:

svetlana [45]3 years ago

6 0

Answer:

Lo lamento tanto, pero no puedo entender la pregunta puedes decirme cual es para poderte ayudar. :)

Step-by-step explanation:

Nat2105 [25]3 years ago

4 0

Oye perdón pero no entiendo...

You might be interested in

Which is the correct answer?

patriot [66]

I think the answer is B

7 0

3 years ago

Whats bigger? -6 or -5????? PLZ HELP

monitta

Answer:

-5 is more positive than -6. SO bigger, I think means less negative, so -5.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

How do you find the radius of a cylinder?

zmey [24]

Answer:

√(V / π × h), where V is the volume of the cylinder, h is the height, and π(Pi) is a mathematical constant with an approximate value of 3.14

7 0

3 years ago

Read 2 more answers

Find each quotient using long division. Just type the number answer in the blank.<br> Pleaseeee help

sergey [27]

Answer: 321 for #1 and 52 for #2

Step-by-step explanation: I divided and got 321 for #1 and 52 for #2.

8 0

3 years ago

The intensity of a light source at a distance is directly proportional to the strength of the source and inversely proportional

jolli1 [7]

Answer:

x= $\frac{16}{\sqrt[3]{2}+1 }$

Step-by-step explanation:

Q= illumination

I = intensity

Q= I/d^2

Q_total = $\frac{I_1}{d_1^2}+\frac{I_2}{d_2^2}$

= $\frac{I}{x^2}+\frac{2I}{(16-x)^2}$

now Q' = 0

⇒I ${-\frac{2}{x^3}}+\frac{4}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

[/tex] $\frac{1}{x^3} = \frac{2}{(16-x)^3}$

x= $\frac{16}{\sqrt[3]{2}+1 }$

is the required point

5 0

2 years ago

Cuanto es dcneicneen eie neim ​

Cuanto es dcneicneen eie neim