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BigorU [14]
3 years ago
14

What expressions from the table are equivalent to that expression ?

Mathematics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

Step-by-step explanation:

11). p^{\frac{3}{5}}\times \sqrt[10]{p^4}

    = p^{\frac{3\times 2}{5\times 2}}\times \sqrt[10]{p^4}

    = p^{\frac{6}{10}}\times \sqrt[10]{p^4}

    = \sqrt[10]{p^{6}}\times\sqrt[10]{p^4}

    = \sqrt[10]{p^{10}}

    = p

    Yes

12). p^{\frac{3}{5}}\times \sqrt[10]{p^4}=\sqrt[5]{p^3} \times \sqrt[10]{p^4}

     But, \sqrt[5]{p^3} \times \sqrt[10]{p^4}\neq \sqrt[3]{p^5}\times \sqrt[10]{p^4}

     No

13). Since, p^{\frac{3}{5}}\times \sqrt[10]{p^4}=p

   Simplify the given expression,

   \sqrt[10]{p^{\frac{23}{5}}}

    \sqrt[10]{p^{\frac{23}{5}}} =p^{\frac{23}{50}}

    No.

14). p^{\frac{12}{50}}=p^{\frac{6}{25}}\neq p

    No.

15). p^{24}\neq p

    No.

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If the public debt of the United States of Apex is 9,529,034,179,824,022 Apex dollars and its gross domestic product (GDP) is 16
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Which function has the greatest rate of change on the interval from x = 3 pi over 2 to x = 2π?
vodka [1.7K]
The average rate of change for the function f(x) can be calculated from the following equation
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By applying the last formula on the given equations 
(1) the first function f
from the table f(3π/2) = -2   and   f(2π) = 0
∴ The average rate of f = \frac{f(2 \pi)-f( \frac{3 \pi}{2} )}{2 \pi -  \frac{3 \pi}{2} } =  \frac{0-(-2)}{ \frac{\pi}{2} }=  \frac{2}{ \frac{\pi}{2} }  =  \frac{4}{\pi}

(2) the second function g(x)
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\pi -  \frac{3 \pi}{2} } =  \frac{0-(-2)}{ \frac{\pi}{2} }=  \frac{2}{ 
\frac{\pi}{2} }  =  \frac{4}{\pi}

(3) the third function h(x) = 6 sin x +1
∴ h(3π/2) = 6 sin (3π/2) + 1 = 6 *(-1) + 1 = -5
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∴ The average rate of h = \frac{f(2 \pi)-f( \frac{3 \pi}{2} )}{2 
\pi -  \frac{3 \pi}{2} } =  \frac{1-(-5)}{ \frac{\pi}{2} }=  \frac{6}{ 
\frac{\pi}{2} }  =  \frac{12}{\pi}

By comparing the results, The <span>function which has the greatest rate of change is h(x)
</span>

So, the correct answer is option <span>C) h(x)</span>
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Answer:

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