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Kisachek [45]
3 years ago
5

Hannah and Ben panned for gold in a mountain stream. Both of them got lucky and found small amounts of gold. Hannah found 0.0045

ounces of gold, and Ben found 1.4 times that amount. How much gold, in ounces, did Ben find?
Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

0.0063

Step-by-step explanation:

first you multiply 0.0045 by 1.4 keeping the decimals lined up and you will get your answer

You might be interested in
Solve the inequality 3>5-b
victus00 [196]

Answer:

I'm pretty sure its b>2

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

3>−b+5

Step 2: Flip the equation.

−b+5<3

Step 3: Subtract 5 from both sides.

−b+5−5<3−5

−b<−2

Step 4: Divide both sides by -1.

-b/-1    <     -2/-1

Answer:

b>2

5 0
2 years ago
How are you in the bet nobody’s not going to help me on this question
Nataliya [291]

Answer:

See below.

Step-by-step explanation:

Party A

y = x^2 + 1

For each value of x in the table, substitute x in the equation with that value and evaluate y.

x = -2: y = (-2)^2 + 1 = 4 + 1 = 5

x = -1: y = (-1)^2 + 1 = 1 + 1 = 2

Do the same for x = 0, x = 1, x = 2

x     y

-2   5

-1    2

0    1

1     2

2    5

Part B

Look at points (-2, 5) and (-1, 2). The change in x from (-2, 5) to (-1, 2) is 1. The change in y is -3.

Now let's look at two other points which have a change in x of 1. Look at points (0, 1) and (1, 2). The change in x from (0, 1) to (1, 2) is 1. The change in y is 1.

You can see that for the first two points, a change of 1 in x produces a change of -3 in y, but for the second two points, the same change of 1 in x produce a change of 1 in y. Since the same change of x does not always produce the same change in y, the function is nonlinear.

Answer: A

4 0
3 years ago
For the question I just asked
guajiro [1.7K]

Answer:

a = 36

Step-by-step explanation:

We use pythagoras theorem here.

h = 60

p = 48

b = a

h² = p² + b²

60² = 48² + b²

3600 = 2304 + b²

b² = 3600 - 2304

b² = 1296

b = 36

7 0
3 years ago
First question, thanks. I believe there should be 3 answers
zysi [14]

Given: The following functions

A)cos^2\theta=sin^2\theta-1B)sin\theta=\frac{1}{csc\theta}\begin{gathered} C)sec\theta=\frac{1}{cot\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

To Determine: The trigonometry identities given in the functions

Solution

Verify each of the given function

\begin{gathered} cos^2\theta=sin^2\theta-1 \\ Note\text{ that} \\ sin^2\theta+cos^2\theta=1 \\ cos^2\theta=1-sin^2\theta \\ Therefore \\ cos^2\theta sin^2\theta-1,NOT\text{ }IDENTITIES \end{gathered}

B

\begin{gathered} sin\theta=\frac{1}{csc\theta} \\ Note\text{ that} \\ csc\theta=\frac{1}{sin\theta} \\ sin\theta\times csc\theta=1 \\ sin\theta=\frac{1}{csc\theta} \\ Therefore \\ sin\theta=\frac{1}{csc\theta},is\text{ an identities} \end{gathered}

C

\begin{gathered} sec\theta=\frac{1}{cot\theta} \\ note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ tan\theta cot\theta=1 \\ tan\theta=\frac{1}{cot\theta} \\ Therefore, \\ sec\theta\ne\frac{1}{cot\theta},NOT\text{ IDENTITY} \end{gathered}

D

\begin{gathered} cot\theta=\frac{cos\theta}{sin\theta} \\ Note\text{ that} \\ cot\theta=\frac{1}{tan\theta} \\ cot\theta=1\div tan\theta \\ tan\theta=\frac{sin\theta}{cos\theta} \\ So, \\ cot\theta=1\div\frac{sin\theta}{cos\theta} \\ cot\theta=1\times\frac{cos\theta}{sin\theta} \\ cot\theta=\frac{cos\theta}{sin\theta} \\ Therefore \\ cot\theta=\frac{cos\theta}{sin\theta},is\text{ an Identity} \end{gathered}

E

\begin{gathered} 1+cot^2\theta=csc^2\theta \\ csc^2\theta-cot^2\theta=1 \\ csc^2\theta=\frac{1}{sin^2\theta} \\ cot^2\theta=\frac{cos^2\theta}{sin^2\theta} \\ So, \\ \frac{1}{sin^2\theta}-\frac{cos^2\theta}{sin^2\theta} \\ \frac{1-cos^2\theta}{sin^2\theta} \\ Note, \\ cos^2\theta+sin^2\theta=1 \\ sin^2\theta=1-cos^2\theta \\ So, \\ \frac{1-cos^2\theta}{sin^2\theta}=\frac{sin^2\theta}{sin^2\theta}=1 \\ Therefore \\ 1+cot^2\theta=csc^2\theta,\text{ is an Identity} \end{gathered}

Hence, the following are identities

\begin{gathered} B)sin\theta=\frac{1}{csc\theta} \\ D)cot\theta=\frac{cos\theta}{sin\theta} \\ E)1+cot^2\theta=csc^2\theta \end{gathered}

The marked are the trigonometric identities

3 0
1 year ago
Javier and his study group designed a word problem, equation, table, and graph that were all supposed to represent the same info
yKpoI14uk [10]

Answer:

Graph

Step-by-step explanation:

for 5 tickets it would cost $40 but on the graph it shows $1.

8 0
3 years ago
Read 2 more answers
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