Answer:
s(t) = -4.9t² + 39.2t
Step-by-step explanation:
Given the projectile motion of an object can be modeled using s(t) = gt2 + v0t + s0, where g is the acceleration due to gravity, t is the time in seconds since launch, s(t) is the height after t seconds, v0 is the initial velocity, and s0 is the initial height. The acceleration due to gravity is –4.9 m/s²
Given
g = -4.9m/s²
v0 = 39.2m/s
s0 = 0m (the initial height)
On substituting into the formula;
s(t) = gt² + v0t + s0
s(t) = -4.9t² + 39.2t + 0
s(t) = -4.9t² + 39.2t
This gives the equation that models the height
Answer:
A) SUBTRACT 3x by both sides of the bottom equation.
Answer:
c
Step-by-step explanation:
I think so I might not be right but I'm sure it's c
Count the distance d, which gives you 7.
Use Pythogarean theorem to find c:
Plug in the numbers:
c is 5.
Same thing with g:
g equals 5.66.
