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igomit [66]
3 years ago
9

Make d the subject of h = d/3 + 2

Mathematics
1 answer:
Bumek [7]3 years ago
6 0

Answer:

D=3(h-2)

Step-by-step explanation:

h=d/3+2

h-2=d/3+2-2

h-2=d/3

3(h-2)=d/3x3

3(h-2)=d

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a total of 10000 was invested in two business ventures A and B .at the of the first year A and B yielded returns of 6% and 23÷4
wolverine [178]

Answer:

(1)

compound amount = 802.5 $

invest earned = 52.5 $

Step-by-step explanation:

total amount = 10000 $

let amount x invested in ventures A and remaining (1000-x) on ventures B

now,

6x/100 +23/400(1000-x ) = 588.75

{24x+23(1000-x)}/400 =588.75

x=235500-230000

x=5500

Amount invested on A = 5500$

Amount invested on B = 4500$

(2)

principle=750$

time= 1 year

effective invest rate = 7%

a) compound amount = p(1+(r/w)^t

=750{1+(7/100)}^1

=802.5$

b) invest earned = 802.5-700 = 52.5$

3 0
3 years ago
Sara is cutting bows out of ribbon which
Andrei [34K]
She can make at least 1 because if u multiple 1/4 and 5 it will give u a decimal as 1.25 or 5/4, or 1
3 0
3 years ago
Read 2 more answers
The mass of a typical raindrop is 8.7 x 10^-5 grams. What is 8.7 x 10^-5 in standard form?
eimsori [14]
Hello There!

8.7 *  10^{-5} is in standard index form.
Standard form is when it is the original number
The '-5' as a power means you need to shift the zero back 5 spaces.
Or, divide by 100,000.
If you do this, you would get 0.000087.

Thus, making it option B.

Hope This Helps You!
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- Hannah ❤
6 0
3 years ago
Read 2 more answers
Y^2 x^3-7x = ysin(x+y)
d1i1m1o1n [39]

Answer: -54

Step-by-step explanation: 53 + 1 = 54

3 0
3 years ago
Romb ma obwód równy 32 cm. Jakie jest pole tego rombu, jeżeli jego wysokość ma 3 cm?
Goshia [24]

Answer:

24 cm²

Step-by-step explanation:

Z zadanego powyżej pytania uzyskano następujące dane:

Obwód (obwód) = 32 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

Następnie określimy długość boku rombu. Można to uzyskać w następujący sposób:

Obwód, czyli obwód (P) = 32 cm

Strona (y) =?

P = 4 s

32 = 4 s

Podziel obie strony przez 4

s = 32/4

s = 8 cm

Stąd długość boku rombu wynosi 8 cm

Na koniec określimy obszar rombu w następujący sposób:

Długość boków = 8 cm

Wysokość (h) = 3 cm

Obszar rombu (A) =?

A = sh

A = 8 × 3

A = 24 cm²

Dlatego obszar rombu jest

24 cm².

8 0
3 years ago
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