Answer:
Class interval 10-19 20-29 30-39 40-49 50-59
cumulative frequency 10 24 41 48 50
cumulative relative frequency 0.2 0.48 0.82 0.96 1
Step-by-step explanation:
1.
We are given the frequency of each class interval and we have to find the respective cumulative frequency and cumulative relative frequency.
Cumulative frequency
10
10+14=24
14+17=41
41+7=48
48+2=50
sum of frequencies is 50 so the relative frequency is f/50.
Relative frequency
10/50=0.2
14/50=0.28
17/50=0.34
7/50=0.14
2/50=0.04
Cumulative relative frequency
0.2
0.2+0.28=0.48
0.48+0.34=0.82
0.82+0.14=0.96
0.96+0.04=1
The cumulative relative frequency is calculated using relative frequency.
Relative frequency is calculated by dividing the respective frequency to the sum of frequency.
The cumulative frequency is calculated by adding the frequency of respective class to the sum of frequencies of previous classes.
The cumulative relative frequency is calculated by adding the relative frequency of respective class to the sum of relative frequencies of previous classes.
3,897.003 in expanded form is:
3,000 + 800 + 90 + 7 + 0.003
8 rock in 5 minutes
54 rocks / 8 rocks = 6.75
6.75 x 5 minutes = 33.75 minutes
Hello :
<span>the nth term of a geometric sequence is :
Un = Up ×r^(n-p) . r is the common ratio
for : p=5 and n= 2
U5 = U2 ×r^3
16 = -2 r^3
r^3 = -8
but : -8 = (-2)^3
so : r = -2
Un = U2 × r^(n-2)
Un = -2 ×(-2)^(n-2)= (-2)^(n-2+1)
</span><span>the nth term of a geometric sequenceis : Un = (-2)^(n-1)</span>
Answer:
Step-by-step explanation:
Given
Reflection across y-axis
Required
Find C'
For reflection across y-axis, the rule is:
So, the image of C is:
Hence:
