Question

(20 points). Some matrixes have very special patterns, for example, in the following matrix, the numbers in the first row are equal to the number of their respective column; the numbers in the first column are equal to the square of the number of their respective row; when the row number equals to the column number, the elements are equal to 1; the rest elements are the sum of the element just above them and the one to their left. Write a user-defined function program in the program, you need to use while loops), and then use the function you write to create the following matrix (show the command you use). 1 4 9 16 2 1 10 26 3 4 1 27 4 5 8 13 9 22 1 23

Answer 1

Answer:

#include <iostream>

using namespace std;

void matrix(){

   int row = 5, col = 6;

   int myarr[row][col];

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           if (i == 0){

               myarr[i][x] = (x+1)*(x+1);

          }else if ( x == 0){

               myarr[i][x] = (i+1)*(i+1)*(i+1);

           } else if ( i == x){

                myarr[i][x] = (i+1);

           } else{

                myarr[i][x] = myarr[i-1][x] + myarr[i][x-1];

           }

        }

   }

   for (int i = 0; i < 5; i++){

       for (int x = 0; x < 6; x++){

           cout<< myarr[i][x] << " ";

       }

       cout<< "\n";

}

}

int main(){

   matrix();

}

Explanation:

The C++ source code defines a two-dimensional array that has a fixed row and column length. The array is a local variable of the function "matrix" and the void function is called in the main program to output the items of the array.