2x + 3y = 6 <=>
3y = -2x + 6 <=>
y = -2/3x + 6/3 <=>
y = -2/3x + 2
The answer is the first one.
Answer: where is statements
Step-by-step explanation:
Answer:
C. 0, -1, 3
Step-by-step explanation:
Note: There is no graph. I assume you mean "zeroes/roots" by "solutions".
x(x^2-2x-3)=0
/(x^2-2x-3)
x=0
x^2-2x-3 = x^2+x-3x-3 = x(x+1) + ( -3(x+1) = (x-3)(x+1)
/(x-3) --> x +1 =0, x=-1
/(x+1) --> x-3 = 0, x=3
