How do you find the lateral surface area of a pyramid? Please help. ):
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The inequality would be 3x(4)-5≤67; the solution is x≤6; the graph is attached.
To solve this, first multiply the coefficients of x:
12x-5≤67
Add 5 to both sides:
12x-5+5≤67+5
12x≤72
Divide both sides by 12:
12x/12 ≤ 72/12
x ≤ 6
To solve this, first multiply the coefficients of x:
12x-5≤67
Add 5 to both sides:
12x-5+5≤67+5
12x≤72
Divide both sides by 12:
12x/12 ≤ 72/12
x ≤ 6