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Arisa [49]
3 years ago
14

A circle has a center located at (-2, 4) and a radius of length 10. Does the point (4, - 4) lie on this circle? Explain how you

arrived at your answer.​
Mathematics
1 answer:
grigory [225]3 years ago
3 0

Answer: Yes, (4, - 4) lies on this circle.

Step-by-step explanation:

Equation of circle:(x-h)^2+(y-k)^2=r^2 , where (h,k) = center , r = radius

Given: A circle has a center located at (-2, 4) and a radius of length 10.

i.e. (h,k) =(-2,4) and r= 10

Equation of circle will be:

(x-(-2))^2+(y-4)^2=10^2\\\\\Rightarrow\ (x+2)^2+(y-4)^2=100 (i)

If (4, - 4) lies on this circle , then it must satisfy the above equation.

To check put x= 4 , y=-4 in (i)

(4+2)^2+(-4-4)^2=100\\\\\Rightarrow\ 6^2+(-8)^2=100\\\\\Rightarrow\ 36+64=100\\\\\Rightarrow\ 100=100 which is true.

Hence, (4, - 4) lies on this circle.

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28m⁷n⁵

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Find the value of<br> 3a²-4ab-26² when A= -1 and b-4
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Substituting the value of a and b

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
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Step-by-step explanation:

<u>Step 1: Define</u>

4x² + 9x - 1 = 0

<u>Step 2: Define variables</u>

a = 4

b = 9

c = -1

<u>Step 3: Find roots</u>

  1. Substitute:                    x=\frac{-9\pm\sqrt{9^2-4(4)(-1)} }{2(4)}
  2. Exponents:                   x=\frac{-9\pm\sqrt{81-4(4)(-1)} }{2(4)}
  3. Multiply:                        x=\frac{-9\pm\sqrt{81-16} }{8}
  4. Subtract:                       x=\frac{-9\pm\sqrt{65} }{8}
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