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3 years ago

In △ABC, point D∈ AB with AD:DB=5:3, point E∈ BC so that BE:EC=1:4. If AABC=40 in2, find AADC, ABDC, and ACDE.

Mathematics

1 answer:

DIA [1.3K]3 years ago

8 0

Answer: Using the proportions between the segments, the area of the triangles are:

1. Area of triangle ADC is 25 in^2.

2. Area of triangle BDC is 15 in^2.

3. Area of triangle CDE is 12 in^2.

Please, see the attached files.

Thanks.

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Solve the equation for x and enter your answer in the box below x + 14 =27

Helen [10]

Answer: x = 13

Step-by-step explanation: When solving an equation like this, we are trying to get our variable which is our letter by itself.

So we first want to ask ourselves what is the 14 doing to x. Well, we can see that it's being added to x so to get x by itself, we will do the opposite of addition which is subtraction. So we subtract 14 from both sides of the equation.

The +14 -14 cancels out so we're left with x on the left.

On the right, we must subtract 14 from 27 to get 13.

So we have x = 13 which is the solution to this equation.

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3 years ago

Read 2 more answers

Write the solution as an inequality -10x>250

jeyben [28]

Answer:

(X<-25) or -oo, -25

Step-by-step explanation:

because max is -25

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2 years ago

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The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

jek_recluse [69]

Answer:

50%

Step-by-step explanation:

68-95-99.7 rule

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$

95% of all values lie within the 1 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$

99.7% of all values lie within the 1 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$

The distribution of the number of daily requests is bell-shaped and has a mean of 55 and a standard deviation of 4.

$\mu = 55\\\sigma = 4$

68% of all values lie within the 1 standard deviation from mean $(\mu-\sigma,\mu+\sigma)$ = $(55-4,55+4)$ = $(51,59)$

95% of all values lie within the 2 standard deviation from mean $(\mu-1\sigma,\mu+1\sigma)$ = $(55-2(4),55+2(4))$ = $(47,63)$

99.7% of all values lie within the 3 standard deviation from mean $(\mu-3\sigma,\mu+3\sigma)$ = $(55-3(4),55+3(4))$ = $(43,67)$

Refer the attached figure

P(43<x<55)=2.5%+13.5%+34%=50%

Hence The approximate percentage of light bulb replacement requests numbering between 43 and 55 is 50%

4 0

3 years ago

For the following exercises, determine whether the functions are even, odd, or neither.

stealth61 [152]

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

2x=20

Divide by 2 on both sides of the equation 2x=20,

$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$

6 0

1 year ago

Clare follows the same workout cycle each time she goes to the gym. First, she runs for 1 3 of an hour. Then, she lifts weights

____ [38]

Answer:

3 times

Step-by-step explanation:

She has 1 1/2 hour to spend in the gym.

1 hr = 60 minute

1/2 of an hour

= 1/2 * 60

= 30 minutes.

In total, she spends 90 minutes in the gym.

If 1/3 of an hour is meant in running, it translates into;

1/3 * 60 = 20 minutes

If 1/6 of an hour is spent in weight-lifting, it translates into;

1/6 * 60 = 10 minutes

In total, she spends,

20 minutes + 10 minutes = 30 minutes for both activities.

To obtain the number of times she would perform both activities, we divide the total amount of time spent in the gym by the amount of time spent for both activities.

= 90 minutes/30 minutes

= 3 times for each cycle.

8 0

2 years ago