Answer:
The parent is x^2
Step-by-step explanation:
We are shifting the function and stretching the function
The parent function is x^2
f(x) = x^2
Then shift
f(x) = (x-9)^2
Then stretch
3 (x-9)^2
I^63
=i*(i^(2*31))
=i*(i^2)^31
i^2=-1
=(-1)^31*i
=-1*i
=-i
A) Y1-Y2/X1-X2
9-4/8-(-2) = 5/10= 1/2
b) 1/2x+b=y <-- plug in a point
1/2(-2)+b=4 <--plugged in (-2,4)
-1+b=4 <-- simplify/solve
b=5
c) 1/2x+5=y
Area of an equilateral triangle is

, where s is length of a side; we have s = 2 + 4 + 2 = 8 mm; then area is

;
Area of a semi-circle = (1/2)π

, where r is the radius of circle; r = 4/2 = 2 mm; then area is 2π;
The shaded area is
![16 \sqrt{3} - 2π = 2( [tex]8 \sqrt{3}](https://tex.z-dn.net/?f=16%20%5Csqrt%7B3%7D%20-%202%CF%80%20%3D%202%28%20%5Btex%5D8%20%5Csqrt%7B3%7D%20)
- π );