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3 years ago

Point I is on line segment HJ. Given HI = x, IJ = 2x + 9, and H J = 4x,

Mathematics

1 answer:

lutik1710 [3]3 years ago

5 0

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length is 199
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first you do this then that

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Given right triangle ABC with altitude BD drawn to hypotenuse AC. If AD = 12

Dmitry [639]

Answer:

x = 6

Step-by-step explanation:

let 'x' = BD

x/3 = 12/x

x² = 36

x = $\sqrt{36}$

x = 6

5 0

3 years ago

Simply 22.5+7(n-3.4)

Bumek [7]

The answer is 7n-1.3. Use the distributive property to multiply 7 by n-3.4. Subtract like terms and it's simplified

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3 years ago

Solve z/5 - 6 = 2 2/3

almond37 [142]

The answer is x= 36 2/3

4 0

3 years ago

Evaluate the following

IRINA_888 [86]

(a) $[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

Answer:

$[\frac{9}{2.6} - \frac{2.5^{2} }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5*2.5 }{2.5} ]^{2}$

= $[\frac{9}{2.6} - \frac{2.5}{1} ]^{2}$

*canceling 2.5 in numerator and denominator*

$= [\frac{9-(2.5)(2.6)}{2.6} ]^2\\*Using L.C.M of 2.6 and 1 which comes out to be '2.6'= [\frac{9-(6.5)}{2.6} ]^2\\= [\frac{2.5}{2.6} ]^2\\*multiplying and dividing by '10'= [\frac{2.5*10}{2.6*10} ]^2\\= [\frac{25}{26} ]^2\\= \frac{25^2}{26^2}\\= \frac{625}{676}\\= 0.925$

Properties used:

Cancellation property of fractions

Least Common Multiplier(LCM)

The least or smallest common multiple of any two or more given natural numbers are termed as LCM. For example, LCM of 10, 15, and 20 is 60.

(b) $[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3} ] ^{2}$

Answer:

$[[\frac{3x^{a}y^{b}} {-3x^{a} y^{b} } ]^{3}] ^{2}\\$

*using $[x^{a}]^b = x^{ab}$ *

$= [\frac{3x^{3a}y^{3b}} {-3x^{3a} y^{3b} }] ^{2}$

*Again, using $[x^{a}]^b = x^{ab}$ *

$= \frac{3x^{2*3a}y^{2*3b}} {-3x^{2*3a} y^{2*3b} } \\= (-1)\frac{3x^{6a}y^{6b}} {3x^{6a} y^{6b} }\\[\tex]*taking -1 common, denominator and numerator are equal*[tex]= -(1)\frac{1}{1}\\= -1$

Property used: 'Power of a power'

We can raise a power to a power

(x^2)4=(x⋅x)⋅(x⋅x)⋅(x⋅x)⋅(x⋅x)=x^8

This is called the power of a power property and says that to find a power of a power you just have to multiply the exponents.

3 0

3 years ago

{(-1, 2), (0, 2), (5, 2)} is a function.

gayaneshka [121]

The relation is a function.

Step-by-step explanation:

As there is only one y-value for every x-value, this is a function

4 0

2 years ago