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WARRIOR [948]
2 years ago
11

Need help. asap. also need an explanation for the problem. :)

Mathematics
1 answer:
Maurinko [17]2 years ago
7 0

Answer:

124858

Step-by-step explanation:

The first 4 digits are simple, you multiply the first digit of the equation by the 2nd digit and then for the other 2 you multiply the first digit of the equation by the 3rd digit.

6 + 2 + 8

6 * 2 = 12

6 * 8 = 48

Then the last 2 digits are the sum of the products of the 1 and 2 and 1 and 3 and subtract it by the 2

12 + 48 = 60

60 - 2 = 58

Put them together

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If granola costs $ 2.20 per pound, how much does 0.8 pound of granola cost?
Elena L [17]
1.76 is the right answer
5 0
3 years ago
Henry went to an amusement park with $150.00 and spent all of it. He spent 1/5 of the money on parking He spent $37.00 on admiss
sashaice [31]

Answer:

8 games

Step-by-step explanation:

According to the problem, calculation of the given data are as follows,

Total amount = $150

Spent on Parking = 1/5 or 20% = $150 × 20% = $30

Spent on admission = $37

Spent on food = 40% = $150 × 40% = $60

Spent on admission in waterpark = $10

Each game cost = $1.5

So, let number of games played be X, then

$30 + $37 + $60 + $10 + $1.5X = $150

$137 + $1.5X = $150

1.5X = $150 - $137

1.5X = $13

X = $13 ÷ 1.5 = 8.67 or 8 games

Hence, Henry can play 8 games.

7 0
3 years ago
Find the perimeter of this please help.
Bezzdna [24]

Answer:

i think the perimeter is 17 hope this helps

4 0
2 years ago
Need Help!!!! Please!!! Explain!!!! Don't Understand!!!
Arturiano [62]

90  it is a right tranigle

6 0
3 years ago
g The tangent plane to z=f(x,y) at the point (1,2) is z=5x+2y−10. (a) Find fx(1,2) and fy(1,2). fx(1,2)= Number fy(1,2)= Number
murzikaleks [220]

Answer:

The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.

Approximation at points (1.1,1.9) is 0.7

Step-by-step explanation:

Given:

Tangent plane to  a surface z=5x+2y-10 as the function at point (1,2)

To find :

f(x,y) at (1,2)

partial derivatives of function w.r.t. (x and y) and value of that function at given points.

Solution:(refer the attachment also)

Now we know that

the equation of tangent plane at given points to the surface is given by,

f(x1,y1,z1) and z=f(x,y)

z-z1=Fx(x1,y1)*(x-x1)+Fy(x1,y1)*(y-y1)

here Fx(x1,y1) and Fy(x1,y1) are the partial derivatives of x and y.

now

taking partial derivative w.r.t. x we get

Fx(x1`,y1)=\frac{d}{dx} (5x+2y-10)

=5.

Then w.r.t y we get

Fy(x1,y1)=

\frac{d}{dy}(5x+2y-10)

=2.

The values for Fx(1,2) and Fy(1,2) are 5 and 2 respectively.

Using the Linearization or linear approximation we get

L(x,y)=f(x1,y1)+Fx(x,y)*(x-x1)+Fy(x,y)(y-y1)

=-1+5(x-1)+2(y-2)

=5x+2y-10

Approximation at F(1.1,1.9)

=5(1.1)+2(1.9)-10

=5.5+3.8-10

=0.7

Approximation at points (1.1,1.9) is 0.7

6 0
3 years ago
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