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3 years ago

HELP!!!!I don’t get it. I need an explanation.

Mathematics

1 answer:

mestny [16]3 years ago

5 0

Answer: 9 is -1

11 is -2 and 13 is -2

Step-by-step explanation:

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David goes into a candy store with $5.00. He buys 9 peppermints for $0.15 each and some sour candies. Each sour candy costs $0.2

Agata [3.3K]

Answer:

5 ≥ 9*.15 + x*.25

He can buy up to 14 candies

Step-by-step explanation:

Total money ≥number of peppermints * cost per peppermint + number of sour candies * cost per sour candy

We know he has 5 dollars. He bought 5 peppermints at $.15 cents each and x sour candies at $.25 each

Substituting in

5 ≥ 9*.15 + x*.25

5≥1.35 + .25x

Subtract 1.35 on each side

5-1.35 ≥ 1.35-1.35+.25x

3.65≥.25x

Divide by .25 on each side

3.65/.25 ≥ .25x/.25

14.6 ≥ x

He can buy up to 14 candies. You can't buy part of a candy

6 0

3 years ago

Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the

AURORKA [14]

Answer:

The standard form of line is

$-3x+y=-2$

Step-by-step explanation:

we are given a line

slope=3

so,

$m=3$

y-intercept of -2

so,

$b=-2$

now, we can use slope-intercept form of line

$y=mx+b$

now, we can plug values

$y=3x-2$

we can write it in standard form of line

$ax+by=c$

$y=3x-2$

we can subtract both sides by 3x

$y-3x=3x-2-3x$

$y-3x=-2$

$-3x+y=-2$

So, the standard form of line is

$-3x+y=-2$

3 0

3 years ago

Read 2 more answers

Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w

pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center $(x_0, y_0)$ and radius r is given by:

$(x - x_0)^2 + (y - y_0)^2 = r^2$

In this problem, the circle is centered at the origin, hence $(x_0, y_0) = (0,0)$ .

The circle contains the point (-13,0), hence the radius is found as follows:

$x^2 + y^2 = r^2$

$(-13)^2 + 0^2 = t^2$

$r^2 = 169$

Hence the equation is:

$x^2 + y^2 = 169$

Then, we test if point (√5, 12) is on the circle:

$x^2 + y^2 = 169$

$(\sqrt{5})^2 + 12^2 = 169$

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0

3 years ago

You have a standard deck of cards. what are the chances that you get a king. Answer in a percent

fenix001 [56]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Find the quotient. -10d ^4e^3f ^5 ÷ 15d ^2e ^2f

Ganezh [65]

Answer:

$16e^{5} d^{6}f^{6}$

Step-by-step explanation:

yeah...

6 0

3 years ago