4z^3 + 5z^2 + z
<span>Well that</span> would be it... <span>not</span> much can be done considering the exponents of the variable :)
Answer:
1%
Step-by-step explanation:
Given : You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
To Find :What is the chance that our interval estimate does not contain the true population mean?
Solution:
We are given that You have used the significant level of 0.01 to estimate the average hours of television viewing for the NJ students.
So, α=0.01
Significance level indicates a risk of concluding that a difference exists when there is no actual difference.
So, The chance that our interval estimate does not contain the true population mean is 0.01
So, The chance that our interval estimate does not contain the true population mean is 
Hence Option D is true
6x+4=4x-2 subtract four x to get 2x+4=-2 and subtract 4 and get -6 and divide it by two to get -3
The probability that the dealership will wait at least 6 months until the next claim is solved by:We know that the mean number of occurrences per time unit is 0.1, then let’s denote this by λ
So: f (x) = 1 – e ^ -λx for x > 0
P (x > 6) = e^ -x
= e ^-0.1 * 6
= 0.5488