Answer:
D) is the answer
Step-by-step explanation:
It is taught in 5th class in India
Mark as Brainliest.
Because I am Indian and solving your question from India.
<span>1. a sine curve with amplitude 2, and period 4pi radians
</span>
the general equation of the sine curve ⇒⇒ y = a sin (nθ)
where: a is the amplitude and n = 2π/perid
∵ <span>amplitude 2, and period 4pi radians
</span>
∴ y = 2 sin (θ/2)
The correct answer is option D. y = 2 sin (θ/2)
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<span>2.The period and amplitude of the function ⇒⇒ y = 5 cos 2θ
</span>
<span>comparing with y = a cos nθ
</span>
where : a is the amplitude and n = 2π/period
<span>amplitude = 5 , period = 2π/n = 2π/2 = π
</span>
The correct answer is option B. Period: pi radians: Amplitude:5
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3. tan (2π/3) = tan 120° = -√3
120° lie in the second quadrant and its reference angle = 180° - 120° = 60°
tan function in the second quadrant is negative
∴ tan 120° = - tan 60 = -√3
The correct answer is C. -sqrt3
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4. <span>Tan 5π/6 = tan 150° = -(√3)/3
</span>
150° lies in the second quadrant and its reference angle = 180° - 150° = 30°
tan function in the second quadrant is negative
∴ tan 150° = - tan 30 = -(√3)/3
The correct answer is <span>B.-sqrt3/3</span>
Answer:
- domain: [0, 7]
- range: [-2, 4]
- is a function? YES
Step-by-step explanation:
The domain is the horizontal extent, which is from x=0 to x=7.
The range is the vertical extent, which is from y=-2 to y=4.
The curve passes the vertical line test, so the relation IS A FUNCTION.
_____
The vertical line test asks whether any vertical line intersects the curve at more than one point. If so, the relation is NOT a function.
Answer:
Step-by-step explanation:
18/3(3)
18/9
2 would be your final answer
