I think The answer is 5100
Answer:
Step-by-step explanation:
In each case we find the discriminant b^2 - 4ac.
If the discriminant is negative, we have two unequal, complex roots.
If the discriminant is zero. we have two equal, real roots.
If the discriminant is positive, we have two unequal real roots.
#51: 8v^2 - 12v + 9: the discriminant is (-12)^2 - 4(8)(9) = -144. we have two unequal, complex roots
#52: (-11)^2 - 4(4)(-14) = 121 + 224 = 345. we have two unequal real roots.
#53: (-5)^2 - 4(7)(6) = 25 - 168 (negative). we have two unequal, complex roots.
#54: (4)^2 - 16 = 0. We have two equal, real roots.
If 68 is a prime number, then the only factors it has are 1 and 68.
If it has any other factors besides 1 and 68, then it's NOT prime.
Right away, without any higher math, you can look at just the last digit
in 68 . The last digit is '8'. That tells you that '68' is an even number,
and THAT tells you that '2' must be one of its factors. So '68' is not a
prime number.
The factors of 68 are 1, 2, 4, 17, 34, and 68 .
68 has four more factors besides 1 and 68, so it's not a prime number.
Oder of operations is this;
W=y (opposite angles are equal)
z=x (opposite angles are equal)
Y= 35
Z= 55
X= 55
S= 35
U= 35
V= 55
T= 55
