Answer:
The correct option is;
D. 6,5
Step-by-step explanation:
TS and TU are midsegments
Segment PR = 18.2
Segment TS = 6.5
Given that TS is the midsegment of PR and PQ, therefore, TS = 1/2×QR
Which gives;
Segment QR = 2×TS = 2 × 6.5 = 13
Segment QR = 13
Given that TU is a midsegment to PQ and QR, we have that QU = UR
Segment QR = QU + UR (segment addition postulate)
Therefore, QR = QU + QU (substitute property of equality)
Which gives;
QR = 2×QU
13 = 2×QU
Segment QU = 13/2 = 6.5
The length of segment QU is 6.5.
Answer:
9/16
Step-by-step explanation:
1) convert 1/8 into 2/16 so denominator are the same
2) then you just add the fractions
Step-by-step explanation:
you work with it like with regular equations :
-9 <= 5 + 2x <= -5
-14 <= 2x <= -10
-7 <= x <= -5
Answer:
B, 
Step-by-step explanation:
Using the law of cosines, which is 
, you can simply insert all the values.
c=|u+v|
a= r value of u (10)
b= r value of v (5)
To find C, you simply have to subtract v from u, and then subtract that number from 180 to find the reference angle.
I.E.: ∠135 - ∠30 = ∠105 ↔ 180 - 105 = 75 = C
so, the completed equation would be 10^{2} + 5^{2}- 2(10)(5)cos(75)
