Answer:
The range of the 95% data (X) = 238.3 days < X < 289.9 days
Step-by-step explanation:
Given;
mean of the normal distribution, m = 264.1 days
standard deviation, d = 12.9 days
between two standard deviation below and above the mean is 96% of all the data.
two standard deviation below the mean = m - 2d
= 264.1 - 2(12.9)
= 238.3 days
two standard deviation above the mean = m + 2d
= 264.1 + 2(12.9)
= 289.9 days
The middle of the 95% of most pregnancies would be found in the following range;
238.3 days < X < 289.9 days
Answer:
0.9 ≈ 90%
Step-by-step explanation:
60% = 60/100
150% of 60% = 150/100 * 60/100
= 9000/10000
= 0.9 ≈ 90%
Answer:
Therefore the greatest number of cookies she can put each bag is 14.
Step-by-step explanation:
Given that Anna has made 30 chocolate chip cookies and 54 sugar cookies.
First we have to find out the number of fried or the number of bags.
So to find the number of bags, We need to find out the G.C.D of 30 and 54.
30=5×3×2
54=3×3×3×2
The common divisor of 30 and 54 is = 3×2 = 6
∴The G.C.D of 30 and 54 is 6.
The number of bags is 6.
The number of chocolate cookies each bags is
=(The number of chocolate cookies÷ 6)
=30÷6
=5
The number of sugar cookies each bags is
=(The number of sugar cookies÷ 6)
=54÷6
=9
Therefore the greatest number of cookies she can put each bag is (5+9)=14.
34%/100=0.34 and that is equal to 34:100 aka 34/100.
Hoped I helped!
Answer:
On the ground is the answer and my chat is "devanson1".
Step-by-step explanation:
without the quotation marks
