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2 years ago

Everyone this person sxtic is a snitch she reports people for no reason. two can play that game.

Mathematics

1 answer:

Fynjy0 [20]2 years ago

4 0

Answer:

thats good to know

Step-by-step explanation:

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35/9 simplified to it’s simplest form

MariettaO [177]

Answer:

$3\frac{8}{9}$

Step-by-step explanation:

5 0

3 years ago

Two lines, A and B, are represented by the following equations:

almond37 [142]

Answer:

Step-by-step explanation:

The solution is where the lines intersect which is at the point (3,2).

So the answer is Option D.

The point (3,2) satisfies both equations.

4 0

3 years ago

Read 2 more answers

The town of Lantana needs $14,000 for a new playground Lantana elementary school raised 5358, Lantana Middle School raised $2,83

slavikrds [6]

Answer: The answer is actually 1,676. But you can estimate it to 2,000. so the town of Lantana would have about 2,000 dollasrs left to raise to reach there goal.

Step-by-step explanation:

You would first make sure you add all the number like 5,358+2,834+4,132. And once you get you answer you subtract 14,000 from the number you got!

I really hope that helps.

8 0

2 years ago

Read 2 more answers

Select ALL of the true statements about the line and it’s equation. ( don’t provide a link it does not work when looking for ans

mr Goodwill [35]

Answer: I need points to give out for answers-

Step-by-step explanation:

7 0

2 years ago

A vertical cylinder is leaking water at a rate of 4m3/sec. If the cylinder has a height of 10m and a radius of 2m, at what rate

Lyrx [107]

Answer:

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

Step-by-step explanation:

Given that a vertical cylinder is leaking water at rate of 4 m³/s.

It means the rate change of volume is 4 m³/s.

$\frac{dV}{dt}=4 \ m^3/s$

The radius of the cylinder remains constant with respect to time, but the height of the water label changes with respect to time.

The height of the cylinder be h(say).

The volume of a cylinder is $V=\pi r^2 h$

$=( \pi \times 2^2\times h)\ m^3$

$\therefore V= 4\pi h$

Differentiating with respect to t.

$\frac{dV}{dt}=4\pi \frac{dh}{dt}$

Putting the value $\frac{dV}{dt}$

$\Rightarrow 4\pi \frac{dh}{dt}=4$

$\Rightarrow \frac{dh}{dt}=\frac{4}{4\pi}$

$\Rightarrow \frac{dh}{dt}=\frac{1}{\pi}$

The rate change of height does not depend on the height.

Therefore the rate change of height is $\frac{1}{\pi}$ m/s.

3 0

2 years ago