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2 years ago

an apartment company has 2 buildings. each building has 3 floors. each floor has 16 windows how many windows are there in total

Mathematics

1 answer:

Licemer1 [7]2 years ago

6 0

Answer:
In total there are 96 window

Explanation:
I’ve attached my work
(Don’t mind my terrible drawing :o )

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At noon (12:00 p.m.), three girls began jogging from the 0 -mile mark of a trail. Each girl jogged at her own steady pace. Drag

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Cindy: 4mph
Taylin: 4m/30 min : 8 mph
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3 years ago

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3 years ago

Which two points in the graphed function have an average rate of change of 5?

djverab [1.8K]

Answer:

<h2>D. points A and B</h2>

Step-by-step explanation:

Look at the picture.

$average\ rate=\dfrac{rise}{run}$

$A.\ B\ and\ C\to\dfrac{-3}{-1}=3\\\\B.\ D\ and\ F\to\dfrac{-12}{2}=-6\\\\C.\ C\ and\ E\to\dfrac{-8}{4}=-2\\\\D.\ A\ and\ B\to\dfrac{-5}{-1}=5$

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3 years ago

Which of the following is a solution to 2cos2x − cos x − 1 = 0?

Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, $x = 0^{\circ}$

Step-by-step explanation:

Given that : $2\cos^2x -\cos x -1 =0$

Let $\cos x =y$

then our equation become;

$2y^2-y-1= 0$ .....[1]

A quadratic equation is of the form:

$ax^2+bx+c =0$ .....[2] where a, b and c are coefficient and the solution is given by;

$x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}$

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

$y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}$

Simplify:

$y = \frac{ 1 \pm \sqrt{1+8}}{4}$

$y = \frac{ 1 \pm \sqrt{9}}{4}$

$y = \frac{ 1 \pm 3}{4}$

$y = \frac{1+3}{4}$ and $y = \frac{1 -3}{4}$

Simplify:

y = 1 and $y = -\frac{1}{2}$

Substitute y = cos x we have;

$\cos x = 1$

⇒ $x = 0^{\circ}$

and

$\cos x = -\frac{1}{2}$

⇒ $x = 120^{\circ} \text{and} x = 240^{\circ}$

The solution set: $\{0^{\circ}, 120^{\circ} , 240^{\circ}\}$

Therefore, the solution for the given equation $2\cos^2x -\cos x -1 =0$ is, $0^{\circ}$

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3 years ago

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a mountaineer climbed 1,000 feet at a rate of x feet per hour, he climbed and additional 5,000 feet at a different rate. this ra

marshall27 [118]

A mountaineer climbed 1000 feet at a rate of x feet/hour

1000 = x ( t 1 ) eq1

5000 = X ( t 2) eq2 ( he climbed additional at different rate )

the rate was 10 feet / hour less than twice the first rate

X = 2x - 10 eq3

take eq1 and eq 2

( total time = t 1 + t 2 = T)

T = 1000/x + 5000/X

but X = 2x-10

T = 1000/x + 5000/( 2x -10)

T = 1000/x + 5000/( 2(x-5))

T = 1000/x + 2500 / (x-5)

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3 years ago

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