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erastovalidia [21]

2 years ago

10

Help me out hereeeeeeee

1 answer:

EleoNora [17]2 years ago

7 0

Answer:

20

Step-by-step explanation:

the factors pairs for 20 are the once above

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Use the identity a^3+b^3=(a+b)^3−3ab(a+b) to determine the sum of the cubes of two numbers if the sum of the two numbers is 4 an

olga55 [171]

Your identity says ...

... sum of cubes = (sum)³ -3(product)(sum)

... = 4³ -3·1·4

... = 64 -12 = 52

_____

The two numbers are 2±√3, and the sum of their cubes is indeed 52.

3 0

3 years ago

Set A={1,2,3,4,5,6} two numbers from set A are selected at random without replacement and their sum recorded how many different

wolverine [178]

The minimum sum is 3 and the maximum is 11. So there are 9 different possible sums.
There are 30 ways to get these 9 different sums.
The table below shows all outcomes.

1 2 3 4 5 6
———————————-
1 | X 3 4 5 6 7
2 | 3 X 5 6 7 8
3 | 4 5 X 7 8 9
4 | 5 6 7 X 9 10
5 | 6 7 8 9 X 11
6 | 7 8 9 10 11 X

6 0

3 years ago

Use the sequence below to answer parts a and b (8,17,26,35,44,53,...) Create an explicit formula to determine the 12th term of t

Andreyy89

THATS HOW YOU SOLVE THE 12TH AND 7TH TERM

8 0

2 years ago

6/22 to the nearest whole percent?<br> is?

Rus_ich [418]

1) Divide the numbers

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3) Round

27.27 is closer to 27

<u><em>Therefore, 6/22 to the nearest whole number is 27%.</em></u>

Hopefully this helps!

4 0

3 years ago

Read 2 more answers

Suppose a simple random sample of size nequals64 is obtained from a population with mu equals 88 and sigma equals 8. (a) Descri

Ulleksa [173]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 88$

$\sigma_{\bar X}= 8$

b) $z=\frac{89.7-88}{\frac{8}{\sqrt{64}}}= 1.7$

$P(Z>1.7) = 1-P(Z$

c) $z =\frac{85.7-88}{\frac{8}{\sqrt{64}}}= -2.3$

$P(Z$

d) $z =\frac{87.35-88}{\frac{8}{\sqrt{64}}}= -0.65$

$z =\frac{90.5-88}{\frac{8}{\sqrt{64}}}= 2.5$

$P(-0.65$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 88, \sigma = 8$

We select a sample size of n = 64

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sample mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 88$

$\sigma_{\bar X}= 8$

Part b

We want this probability:

$P(\bar X>89.7)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89.7 we got:

$z=\frac{89.7-88}{\frac{8}{\sqrt{64}}}= 1.7$

$P(Z>1.7) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 85.7 we got:

$z =\frac{85.7-88}{\frac{8}{\sqrt{64}}}= -2.3$

$P(Z$

Part d

We want this probability:

$P(87.35$

We find the z scores:

$z =\frac{87.35-88}{\frac{8}{\sqrt{64}}}= -0.65$

$z =\frac{90.5-88}{\frac{8}{\sqrt{64}}}= 2.5$

$P(-0.65$

6 0

2 years ago