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3 years ago

How do I solve this?!

Mathematics

1 answer:

jarptica [38.1K]3 years ago

8 0

I think its 3 because if it was 2, the other frequencies would go hay-wire!
and the other 2 choices are completely irrelevant

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Suppose u1, u2, ..., un are independent random variables and for every i = 1, ..., n, ui has a uniform distribution over [0, 1].

sattari [20]

$Z=U_{(1)}=\min\{U_1,\ldots,U_n\}$

has CDF

$F_Z(z)=1-(1-F_{U_i}(z))^n$

where $F_{U_i}(u_i)$ is the CDF of $U_i$ . Since $U_i$ are iid. with the standard uniform distribution, we have

$F_{U_i}(u_i)=\begin{cases}0&\text{for }u_i$

and so

$F_Z(z)=1-(1-F_{U_i}(z))^n=\begin{cases}0&\text{for }z$

Differentiate the CDF with respect to $z$ to obtain the PDF:

$f_Z(z)=\dfrac{\mathrm dF_Z(z)}{\mathrm dz}=\begin{cases}n(1-z)^{n-1}&\text{for }0$

i.e. $Z$ has a Beta distribution $\beta(1,n)$ .

3 0

3 years ago

Exercise 1: In the right triangle below, calculate the measurement of the unknown side. Show your work.

vekshin1

Answer:

Exercise 1:

base [b]=8cm

perpendicular [p]=6cm

hypotenuse [h]=?

By using Pythagoras law

h²=p²+b²

h²=6²+8²

h=√100

h=10cm

So another side's length is 10cm

Exercise 2:

base [b]=6m

perpendicular [p]=bm

hypotenuse [h]=8m

By using Pythagoras law

h²=p²+b²

8²=b²+6²

b²=8²-6²

b=√28=2√7 0r 5.29 or 5.3

So height of kite is√28or 2√7 0r 5.29 or 5.3 m

Step-by-step explanation:

[Note: thanks for translating]

4 0

3 years ago

Review the diagram below.

morpeh [17]

Answer:

the asnwer is 35°

Step-by-step explanation:

you can said bca and its gonna give you that

7 0

3 years ago

Read 2 more answers

Find an equivalent fractions for each given fraction 70/10

ivanzaharov [21]

Answer:

140/20

Step-by-step explanation:

If you reduce the fraction your left with just 7

7 0

3 years ago

Can anyone help me? Brainlist if right! Thx :)

tamaranim1 [39]

Answer:

odd: 4/7

not 3: 6/7

4 or 5: 2/7

spinner spun 2: there both 1/7 i think im

only in 7th grade ;-;

Step-by-step explanation: well there are 7 spaces so the probabilty

of it landing on an odd space on the wheel is how many odd numbers there are over 7 . and there is only 1 three so the chance that it will not land on 3 is 6/7. there is a 2/7 chance it will land on 4 or 5. and im not to sure abt the last one but like i said im only in the 7th grade i am taking p classes tho so the rest should be right. :D

4 0

3 years ago