Answer:
The point estimate for this problem is 0.48.
Step-by-step explanation:
We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.
A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".
<em>Let </em>
<em> = proportion of students who felt comfortable reporting cheating by their fellow students</em>
<u></u>
<u>Now, point estimate (</u><u>) is calculated as;</u>
where, X = number of students who answered yes = 1,344
n = number of students surveyed = 2,800
So, Point estimate () = 
= <u>0.48 or 48%</u>
Answer: probability = 0.506
Step-by-step explanation:
The data we have is:
Total people: 205 + 160 + 40 = 405
prefer cats: 205
prefer dogs: 160
neither: 40
The probability that a person chosen at random prefers cats is equal to the number of people that prefer cats divided the total number of people:
p = 205/405 = 0.506
in percent form, this is 50.6%
Answer:9 1/2
Step-by-step explanation:
Answer:
$24
Step-by-step explanation:
Since you know 5 tickets equal to $60, and you want to find the cost of one ticket, you would divide 60 by 5. 60/5=12. So each ticket costs 12 dollars. But you want to find the cost of two. So multiply $12 by two to get $24 dollars per two tickets.
The answer is 1
Hope this helped :)
