2 years ago

Can anybody help me with these two questions

Mathematics

1 answer:

sladkih [1.3K]2 years ago

4 0

Answer:

#1 is 39

#2 is 10 1/2

Step-by-step explanation:

Hopefully this helped, if not HMU and I will try my best to get you a better answer!

Have a great thanksgiving break :)

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Please help! (I'll give brainliest to the first right answer.)

a_sh-v [17]

Answer:

1. 2,3; -2, 3

2. Both points share common values, but their absolute values for the x-value vary.

3. 2,3; 2, -3

4. Both points share common values, but their absolute values for the y-value vary.

Step-by-step explanation:

For 1, the answer is thus:

-On the graph, the original point is 2, 3.

-A reflection over the y-axis changes the x-value, so it would be -2,3.

Similar for the next chart:

-The initial point is 2,3.

-A reflection over the x-axis changes the y-value, so the reflected point would be 2, -3.

The explanation is:

Both points have similar values except with differences in the absolute value.

Hope this helps you.

3 0

2 years ago

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Stanley is reading a 224-page book. There are illustrations on 14 pages. If Stanley opens the book at random, what is the probab

likoan [24]

It will be 0.0625 because you can use a calculator and do 14/224

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2 years ago

Express the following as percentages. (i) 12 hours in 3 days

Zolol [24]

Hope it helps you buddy

6 0

2 years ago

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I can't quite remember how to approach this one, I have three others, but I think I could solve them if someone helped walked me

Nimfa-mama [501]

Https://us-static.z-dn.net/files/d8d/e008ced388704d59896d3bf37158f465.jpeg

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2 years ago

Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are sel

Andre45 [30]

Answer:

Step-by-step explanation:

Given

there are six integers to win a lottery

case-1 Integer not exceeding 40

no of ways to choose 6 incorrect numbers

$=\dfrac{^{34}C_{6}}{^{40}C_{6}}$

$=0.35$

Case-2 no of ways to choose 6 incorrect numbers out of 48 integers

$=\dfrac{^{42}C_{6}}{^{48}C_{6}}$

$=0.427$

Case-3 no of ways to choose 6 incorrect numbers out of 56 integers

$\dfrac{^{50}C_{6}}{^{56}C_{6}}$

$=0.489$

Cae-4 no of ways to choose 6 incorrect numbers out of 64 integers

$\dfrac{^{58}C_{6}}{^{64}C_{6}}$

$=0.54$

6 0

3 years ago

Can anybody help me with these two questions​

Can anybody help me with these two questions