Answer: With 11 pipes, you need 31.82 minutes to fill the tank.
Step-by-step explanation:
Let's define R as the rate at which one single pipe can fill a tank.
We know that 7 of them can fill a tank in 50 minutes, then we have the equation:
7*R*50min = 1 tank
Whit this equation, we can find the value of R:
R = 1 tank/(7*50min) = (1/350) tank/min.
Now that we know the value of R, we can do the same calculation but now with 11 pipes.
Then the time needed to fill the tank, T, is such that:
11*(1/350 tank/min)*T = 1 tank
We need to isolate T.
T = 1 tank/(11*(1/350 tank/min)) = 31.82 min
With 11 pipes, you need 31.82 minutes to fill the tank.
X= -5 because you divide -5x by -5 to get x alone so you have to 25/-5 which is -5
5000
- Addition (+) and subtraction (-) round by the least number of decimals.
- Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
- Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
- Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
- Exponentiation (n^x) only rounds by the significant figures in the base.
- To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
- Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
- Rounds when required, after parentheses, and on the final step.
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Answer:
Option C. is correct
Step-by-step explanation:
In the triangle ABC, vertices are A(12, 8), B(4, 8) and C(4, 14)
AB =
BC =
AC =
In triangle XYZ vertices are X(6,6), Y(4,12) and Z(10, 14)
XY =
YZ =
XZ =
In triangle MNO, vertices are M(4, 16), N(4, 8) and O(-2, 8)
MN =
MO =
NO =
In triangle JKL, vertices are J(14, -2), K(12,2) and L(20, 4)
JK =
KL =
JL =
Now we compare the sides for the congruence
Since AB = MN = 8
BC = NO = 6
AC = OM = 10
So ΔABC ≅ Δ MNO
Option C. is correct
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