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Mathematics

1 answer:

xeze [42]3 years ago

7 0

The answer to one is b. I recommend using a website called Desmos when you have to do things with equations. It has been very helpful to me and gives you the answer automatically. Even teachers recommend it.

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1. The table shows the probabilities of a response chocolate or vanilla when asking a child or adult. Use the formula for condit

Stels [109]

$\begin{matrix}&\text{chocolate}&\text{vanilla}&\text{total}\\\text{children}&0.14&0.26&0.40\\\text{adults}&0.21&0.39&0.60\\\text{total}&0.35&0.65&1.00\end{matrix}$

a. "Chocolate" and "Adults" (whatever those mean) will be independent as long as

$P(\text{chocolate}\cap\text{adults})=P(\text{chocolate})\cdot P(\text{adults})$

"Chocolate" has the marginal distribution given by the second column, with a total probability of $P(\text{chocolate})=0.35$ . Similarly, "Adults" has the marginal distribution described by the third row, so that $P(\text{adults})=0.60$ . Then

$P(\text{chocolate})\cdot P(\text{adults})=0.35\cdot0.60=0.21$

Meanwhile, the joint probability of "Chocolate" and "Adults" is given by the cell in the corresponding row/column, with $P(\text{chocolate}\cap\text{adults})=0.21$ .

The probabilities match, so these events are indeed independent.

Parts (b) and (c) are checked similarly.

b. Yes;

$P(\text{children})\cdot P(\text{chocolate})=0.40\cdot0.35=0.14$
$P(\text{children}\cap\text{chocolate})=0.14$

c. Yes;

$P(\text{vanilla})\cdot P(\text{children})=0.65\cdot0.40=0.26$
$P(\text{vanilla}\cap\text{children})=0.26$

5 0

3 years ago

What quantity of strawberries would you need to make 4 times as much as the original recipe?

KengaRu [80]

Answer:

2 pounds of strawberries

Step-by-step explanation:

3 0

3 years ago

How am I supposed to do this?

Snezhnost [94]

Take it step by step by doing the 2 fractions on top