Given:
Two similar rectangles.
To find:
The area of the larger rectangle.
Solution:
Let x be the other side of the larger rectangle.
Corresponding sides of similar figures are always congruent.
![\dfrac{x}{1}=\dfrac{4}{2}](https://tex.z-dn.net/?f=%5Cdfrac%7Bx%7D%7B1%7D%3D%5Cdfrac%7B4%7D%7B2%7D)
![x=2](https://tex.z-dn.net/?f=x%3D2)
The other side of larger rectangle is 2 cm.
We know that, area of rectangle is
![Area=Length\times Width](https://tex.z-dn.net/?f=Area%3DLength%5Ctimes%20Width)
So, area of the larger rectangle is
![Area=4\times 2](https://tex.z-dn.net/?f=Area%3D4%5Ctimes%202)
![Area=8](https://tex.z-dn.net/?f=Area%3D8)
Therefore, the area of the larger rectangle is 8 sq. cm.
Answer:
x = 14.7
Step-by-step explanation:
Use Law of Sines.
7/sin20=x/sin46
cross multiply
7sin46=xsin20
divide both sides by sin20 to isolate x
x = 7sin46/sin20
x = 14.72
Divide
8/1 / 2/3
Keep change flip
8/1 x 3/2
Simplify
4/1 x 3/1
12/1
He can make 12 2/3 ounce peanuts with 8 ounces of peanuts.