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2 years ago

Please answer ive been waiting half hour

Mathematics

2 answers:

kvv77 [185]2 years ago

8 0

The subject is the idea,being or thing being discussed.

Should be "plant". Its the Main thing being discussed.

Oksana_A [137]2 years ago

7 0

I’m pretty sure it’s plant

You might be interested in

I need help with this question asap

Nataly_w [17]

Answer:

The correct answer would be the bottom equation.

Step-by-step explanation:

y=7.25x

y=7.25(3)

y=21.75

y=7.25(4)

y=29.00

y=7.25(5)

y=36.25

7 0

3 years ago

Help me with this please

liraira [26]

Answer:

Step-by-step explanation:

the data value of x is 0 the the value would be .75 times that by 2 get 1.25

8 0

3 years ago

I need help with the incorrect ones please

Morgarella [4.7K]

Answer:

73.6

61.824

.2776

2.3

1.342

.4129

*note* I had trouble reading the standard deviation of the second part, so if it's not 3 then leave a comment and i will fix it*

Step-by-step explanation:

1.)

the mean would be something like 460*.16= 73.6

The variance should be 460*.16(1-.16)= 61.824 which means the standard deviation is √61.824= 7.863

for p to be less than .15 it would have to be less than .15*460= 69

(69-73.6)/7.863= -.59 which has a probability of .2776

2.)

the mean is 2.3

I am not sure if the standard deviation is 3 or .3 (picture is kind of blurry)

I am thinking that it's three which would mean that the standard deviation would be √(3²*(1/5))= 1.342

(2-2.3)/1.342= -.22 = .4129

5 0

2 years ago

Assume that different groups of couples use the XSORT method of gender selection and each couple gives birth to one baby. The XS

olganol [36]

Answer:

Mean and Standard deviation for the numbers of girls in groups of 36 births are 18 and 3 respectively.

Step-by-step explanation:

We are given that he X SORT method is designed to increase the likelihood that a baby will be a girl, but assume that the method has no effect, so the probability of a girl is 0.5.

Now consider a group consisting of 36 couples.

The above situation can be represented through binomial distribution;

$P(X=r)=\binom{n}{r} \times p^{r} \times (1-p)^{n-r} ;x=0,1,2,3,.....$

where, n = number of trials (samples) taken = 36 couples

r = number of success

p = probability of success which in our question is probability

of a girl, i.e.; p = 0.5

Let X = Numbers of girls in groups of 36 births

So, X ~ Binom(n = 36, p = 0.5)

Now, mean for the numbers of girls in groups of 36 births is given by;

Mean, E(X) = $n \times p$ = $36 \times 0.5$ = 18

Also, standard deviation for the numbers of girls in groups of 36 births is given by;

Standard deviation, S.D.(X) = $\sqrt{n\times p\times (1-p)}$

= $\sqrt{36\times 0.5\times (1-0.5)}$

= 3

3 0

3 years ago

Learning Task 4. Solve the problem by applying the sum and product of roots

Delvig [45]

Answer:

Thus, the dimensions of the metal plate are 10 dm and 8 dm.

Step-by-step explanation:

For a quadratic equation:

$x^2+bx+c=0$

The sum of the roots is -b and the product is c. Note the leading coefficient is 1.

We know the perimeter of the rectangular metal plate is 36 dm and its area is 80 dm^2. Being L and W its dimensions, then:

P=2(L+W)=36

A=L.W=80

Note both formulas are closely related to the roots of the quadratic equation, we only need to adjust the data for the perimeter to be exactly the sum of L+W and not double of it.

Thus we use the semi perimeter instead as P/2=L+W=18

The quadratic equation is, then:

$x^2-18x+80=0$

Factoring by finding two numbers that add up to 18 and have a product of 80:

$(x-10)(x-8)=0$

The solutions to the equation are:

x=10, x=8

Thus, the dimensions of the metal plate are 10 dm and 8 dm.

6 0

3 years ago