40-15=g so they scored 25 this year and 25+15=40
Answer:
p
8
Step-by-step explanation:
Answer:
a) (1215, 1297)
b) (1174, 1338)
c) (1133, 1379)
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 1256
Standard Deviation, σ = 41
Empirical Rule:
- Also known as 68-95-99.7 rule.
- It states that almost all the data lies within three standard deviation for a normal data.
- About 68% of data lies within 1 standard deviation of mean.
- About 95% of data lies within two standard deviation of mean.
- About 99.7% of data lies within 3 standard deviation of mean.
a) range of years centered about the mean in which about 68% of the data lies
![\mu \pm 1(\sigma)\\=1256 \pm 41\\=(1215, 1297)](https://tex.z-dn.net/?f=%5Cmu%20%5Cpm%201%28%5Csigma%29%5C%5C%3D1256%20%5Cpm%2041%5C%5C%3D%281215%2C%201297%29)
68% of data will be found between 1215 years and 1297 years.
b) range of years centered about the mean in which about 95% of the data lies
![\mu \pm 2(\sigma)\\=1256 \pm 2(41)\\=1256 \pm 82\\=(1174, 1338)](https://tex.z-dn.net/?f=%5Cmu%20%5Cpm%202%28%5Csigma%29%5C%5C%3D1256%20%5Cpm%202%2841%29%5C%5C%3D1256%20%5Cpm%2082%5C%5C%3D%281174%2C%201338%29)
95% of data will be found between 1174 years and 1338 years.
c) range of years centered about the mean in which about all of the data lies
![\mu \pm 3(\sigma)\\=1256 \pm 3(41)\\=1256 \pm 123\\=(1133, 1379)](https://tex.z-dn.net/?f=%5Cmu%20%5Cpm%203%28%5Csigma%29%5C%5C%3D1256%20%5Cpm%203%2841%29%5C%5C%3D1256%20%5Cpm%20123%5C%5C%3D%281133%2C%201379%29)
All of data will be found between 1133 years and 1379 years.
Answer:
A. 6y
Step-by-step explanation:
The profit formula is: total earnings- total expenses. In this case the 145 has a minus sign, which indicates that these are Debra's total expenses. Then, 6y represents total revenue. You can also identify that this is the answer because revenues depend on babysitting hours, which in this case, is represented by the variable "y".
Answer:
On his 6th birthday, he was 45 inches tall
Step-by-step explanation: