<h3>
Answer:</h3>
- B. f(x) = 3,000(0.85)^x
- $1566.02
<h3>
Step-by-step explanation:</h3>
Part A
At the end of the year, the value of the computer system is ...
... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)
... = 0.85 · (beginning value)
Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...
... f(x) = (beginning value) · 0.85^x
The beginning value is given as $3000, so this is ...
... f(x) = 3000·0.85^x
____
Part B
For x=4, this is ...
... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02
The value after 4 years is $1566.02.
Answer:
The answer to your question is below
Step-by-step explanation:
2. 
Just find the prime factors of 128 and simplify
3.- 
Get the square roots and simplify
3i + 4i
7i
4.- None of the choices is equal to one, because the exponents are pair.
5.- 1/3x² + 10 = 7
1/3x² = 7 - 10
1/3x² = -3
x² = -3(3)
x² = -9
x = ±3i
Answer:
sorry but i cant see what you have can you try again?
Step-by-step explanation:
Answer:
12 years = 16 USD
15 years = 20 USD
Step-by-step explanation:
15 years =72:4= 18 we round to 20 for 15 years
12 years = 20+20 = 40
72-40 = 32 : 2 = 16 USD for 12 years
