(×+2) +(4×-122)=180 need help with this problem

1 answer:

6 0

So first you need to open the brackets, so it would be x+2+4x-122=180. Then we can add the 4x and the other x to make 5x, and then by doing 2-122 we get -120. This gives us the equation 5x-120=180. We then isolate the variable by moving the -120 to the other side of the equation and becoming a positive, so it would look like 5x=180+120. Then, we have 5x=300. 300 divides by 5 is 60 making X=60. Hope this helps!

You might be interested in

jack obtains a loan of $4815.16 at 2.3% ordinary interest for 42 days. what is the maturity value of the loan

il63 [147K]

The maturity value is 4827 and if needed interest value is 12.

4 0

3 years ago

Haryati had 1250 oranges.

Blababa [14]

First you subtract 242 from 1250 which gives you 1080. Then you divide it by 8 which gives you 126. Multiply this value by 3 and this shows that Haryati received $378. Hope this is helpful.

7 0

3 years ago

Help with geometry hw

love history [14]

A and a' are vertical angles, therefore a' = a

We know: The sum of the measures of triangle is always 180°.

Therefore: a' + b + d = 180° → d = 180° - a - b.

d and c are adjacent angles, therefore d + c = 180°

substitute

180° - a - b+ c = 180° |-180°
-a - b + c = 0 |+a |+b
c = a + b

4 0

3 years ago

PLEAS EHELP, NO LINK ANSWERS I WILL GIVE BRAINLY THING

Agata [3.3K]

Answer:

H2O and CO2 are examples of compounds

as the have different elements combined in them, and they don't show properties of combining elements..

4 0

2 years ago

Using the Factor Theorem, which of the polynomial functions has the zeros 2, radical 3 , and negative radical 3 ? f (x) = x3 – 2

Basile [38]

Answer:

$f(x) = x^3 - 2x^2 -3x + 6$

Step-by-step explanation:

According to the Factor Theorem, if (x - k) is a factor of a polynomial P(x), then P(k) must equal zero.

We are given that a polynomial function has the zeros 2, √3, and -√3. So, we can let k = 2, √3, -√3.

So, according to the Factor Theorem, P(2), P(√3) and P(-√3) must equal 0.

Testing each choice, we can see that only A is true:

$\displaystyle f(x) = x^3 - 2x^2 - 3x + 6$

Testing all three values yields that:

$\displaystyle \begin{aligned} f(2) &= (2)^3 - 2(2)^2 -3(2) + 6 \\ &= (8) - (8) -(6) + (6) \\ &= 0\stackrel{\checkmark}{=}0 \\ \displaystyle f(\sqrt{3}) &= (\sqrt{3})^3 - 2(\sqrt{3})^2 - 3(\sqrt{3}) + 6 \\ &=(3\sqrt{3}) -(6)-(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \\ f(-\sqrt{3}) &= (-\sqrt{3})^3 - 2(-\sqrt{3})^2 - 3(-\sqrt{3}) + 6 \\ &=(-3\sqrt{3}) -(6)+(3\sqrt{3}) + 6 \\ &= 0\stackrel{\checkmark}{=}0 \end{aligned}$

Hence, our answer is A.

3 0

2 years ago