1. Write an equivalent expression to 2x + 3 + 5x + 6 by combining like terms. What is the answer?

If a solid has faces that consist of 2 equilateral triangles and 3 congruent rectangles, what type of solid is it?

Burka [1]

A right triangular prism is a solid that has faces that consist of 2 equilateral triangles and 3 congruent rectangles. It is also described to have two parallel faces, and 3 other faces that belong to the same place (and are not parallel to the parallel pair of faces).

7 0

4 years ago

The inhabitants of the island of jumble use the standard kobish alphabet ($20$ letters, a through t). each word in their languag

rjkz [21]

We know that

1. The number of all 4-letter words written using the alphabet of 20 symbols (from A to T) is
20^4=160,000

2. The number of all 4-letter words written using the alphabet of 19 symbols (from B to T) is
19^4=130,321

3. The difference represents exactly the number of all words of the inhabitants of the island of Jumble
difference=(160,000-130,321)= 29679.

the answer is
29679

7 0

3 years ago

A cigarette industry spokesperson remarks that current levels of tar are no more than 5 milligrams per cigarette. A reporter doe

d1i1m1o1n [39]

Answer:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

$df=n-1=15-1=14$

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

Step-by-step explanation:

Data given and notation

$\bar X=5.63$ represent the sample mean

$s=1.61$ represent the standard deviation for the sample

$n=15$ sample size

$\mu_o =15/tex] represent the value that we want to test 
[tex]\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the average is more than 5.63, the system of hypothesis would be:

Null hypothesis: $\mu \leq 5.63$

Alternative hypothesis: $\mu > 5.63$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{5.63-5}{\frac{1.61}{\sqrt{15}}}=1.516$

Now we need to find the degrees of freedom for the t distribution given by:

$df=n-1=15-1=14$

P value

Since is a right tailed test the p value would be:

$p_v =P(t_{14}>1.516)=0.076$

If we use a significance level of 0.05 we see that $p_v > \alpha$ and then we can conclude that we don't have evidence in order to conclude that the mean is higher than 5.63, so then the claim makes sense.

3 0

3 years ago

I dont get my mom doesn't get this help me pls

Mariana [72]

5. C. Liquid 2 because 3ml = 1g, 6ml = 2g

6 C. Lead because 75.7 divided by 6.7 = 11.3

7. C. Copper because 89 divided by 10 = 8.9

6 0

3 years ago

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John Jones has decided to go into the bussiness of producing and selling boats.In order to begin this venture, he must invest 10

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