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Mashutka [201]
2 years ago
13

Which of the following is equal to 2?

Mathematics
2 answers:
AnnZ [28]2 years ago
8 0
Awnser is A 6+4 divided by [2+1]x3
astraxan [27]2 years ago
7 0
Answer A because 6+4 divided by (2+1)x3 is 2
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I am looking for an answer key to a 10th grade online school Geometry video organizer. It's a 25 page packet. Attached is the fi
gladu [14]

Answer:

I found a pdf that has the lesson overview I just searched up:

Geometry 1e elayn martin gay section 4.1 types of triangles answer sheet

5 0
3 years ago
I'm trying to find out the number of how much it cost to wrap each present, day one 41 small gifts were wrapped and 45 large wer
Licemer1 [7]

Answer:

Small gift: $2

Large gift: $7

Step-by-step explanation:

Let x represent cost of wrapping each small gift and y represent cost of wrapping each large gift.

We have been given that day one 41 small gifts were wrapped and 45 large were wrapped equaling $397.

We can represent this information in an equation as:

41x+45y=397...(1)

We are also told that day two 30 small gifts were wrapped and 47 large were wrapped equaling $389. We can represent this information in an equation as:

30x+47y=389...(2)  

From equation (1), we will get:

x=\frac{397-45y}{41}

Upon substituting this value in equation (2), we will get:

30(\frac{397-45y}{41})+47y=389

\frac{11910-1350y}{41}+\frac{47*41y}{41}=389

\frac{11910-1350y+1927y}{41}=389

\frac{11910+577y}{41}=389

\frac{11910+577y}{41}\cdot 41=389\cdot 41

11910+577y=15949

11910-11910+577y=15949-11910

577y=4039

\frac{577y}{577}=\frac{4039}{577}

y=7

Therefore, cost to wrap a large gift is $7.

Upon substituting y=7 in equation x=\frac{397-45y}{41}, we will get:

x=\frac{397-45(7)}{41}

x=\frac{397-315}{41}

x=\frac{82}{41}

x=2

Therefore, cost to wrap a small gift is $2.

8 0
3 years ago
Determine the location and values of the absolute maximum and absolute minimum for given function : f(x)=(‐x+2)4,where 0<×&lt
brilliants [131]

Answer:

Where 0 < x < 3

The location of the local minimum, is (2, 0)

The location of the local maximum is at (0, 16)

Step-by-step explanation:

The given function is f(x) = (x + 2)⁴

The range of the minimum = 0 < x < 3

At a local minimum/maximum values, we have;

f'(x) = \dfrac{(-x + 2)^4}{dx}  = -4 \cdot (-x + 2)^3 = 0

∴ (-x + 2)³ = 0

x = 2

f''(x) = \dfrac{ -4 \cdot (-x + 2)^3}{dx}  = -12 \cdot (-x + 2)^2

When x = 2, f''(2) = -12×(-2 + 2)² = 0 which gives a local minimum at x = 2

We have, f(2) = (-2 + 2)⁴ = 0

The location of the local minimum, is (2, 0)

Given that the minimum of the function is at x = 2, and the function is (-x + 2)⁴, the absolute local maximum will be at the maximum value of (-x + 2) for 0 < x < 3

When x = 0, -x + 2 = 0 + 2 = 2

Similarly, we have;

-x + 2 = 1, when x = 1

-x + 2 = 0, when x = 2

-x + 2 = -1, when x = 3

Therefore, the maximum value of -x + 2, is at x = 0 and the maximum value of the function where 0 < x < 3, is (0 + 2)⁴ = 16

The location of the local maximum is at (0, 16).

5 0
3 years ago
Kaitlyn works mowing laws and babysitting. She earns $7.90 an hour for mowing and $6.80 an hour for babysitting. How much will s
Alona [7]
7.90×7=55.30. 6.80×1=6.80. 55.30 + 6.80=62.10 Total
4 0
3 years ago
What is the formula to <br>u-5=-4(w-1)
erastovalidia [21]

Answer: u = -4w + 9

<u>Step-by-step explanation:</u>

u - 5 = -4(w - 1)

u - 5 = -4w + 4

<u>   +5 </u>    <u>       +5  </u>

u         = -4w + 9

3 0
3 years ago
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