BRAIN TO CORRECT ANSWER!!

Question 1 2XY3 + 3XY3 5X2Y6 True or False

Law Incorporation [45]

U believe it’s F....

5 0

3 years ago

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Given the following diagram, find the missing measure. *

BigorU [14]

Option C:

x = 30

Solution:

The given image is a triangle.

angle 1, angle 2 and angle 3 are interior angles of a triangle.

angle 4 is the exterior angle of a triangle.

m∠4 = 2x°, $m\angle2=\frac{4}{3}x^\circ$ , m∠3 = 20°

Exterior angle theorem:

In triangle, the measure of exterior angle is equal to the sum of the opposite interior angles.

By this theorem,

m∠4 = m∠2 + m∠3

$$2x^\circ=\frac{4}{3}x^\circ+20^\circ$

Subtract $\frac{4}{3}x^\circ$ on both sides of the equation.

$$2x^\circ-\frac{4}{3}x^\circ=20^\circ$

To make the denominator same and then subtract.

$$\frac{6}{3}x^\circ -\frac{4}{3}x^\circ=20^\circ$

$$\frac{2}{3}x^\circ =20^\circ$

Multiply by $\frac{3}{2}$ on both sides of the equation.

x° = 30°

x = 30

Hence option C is the correct answer.

6 0

3 years ago

Solve for f. 9f = 8f + 8 f

Svet_ta [14]

Answer:

f = 8

Step-by-step explanation:

9f = 8f + 8

9f - 8f

= f

So, f = 8

9(8) = 8(8) + 8

72 = 72

6 0

3 years ago

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The coordinates G(7,3), H(9, 0), (5, -1) form what type of polygon?

Marrrta [24]

Answer:

Is an acute triangle

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

G(7,3), H(9, 0), I(5, -1)

step 1

Find the distance GH

substitute in the formula

$d=\sqrt{(0-3)^{2}+(9-7)^{2}}$

$d=\sqrt{(-3)^{2}+(2)^{2}}$

$GH=\sqrt{13}\ units$

step 2

Find the distance IH

substitute in the formula

$d=\sqrt{(0+1)^{2}+(9-5)^{2}}$

$d=\sqrt{(1)^{2}+(4)^{2}}$

$IH=\sqrt{17}\ units$

step 3

Find the distance GI

substitute in the formula

$d=\sqrt{(-1-3)^{2}+(5-7)^{2}}$

$d=\sqrt{(-4)^{2}+(-2)^{2}}$

$GI=\sqrt{20}\ units$

step 4

Verify what type of triangle is the polygon

we know that

If applying the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$ ----> is a right triangle

$c^{2}> a^{2}+b^{2}$ ----> is an obtuse triangle

$c^{2}< a^{2}+b^{2}$ ----> is an acute triangle

where

c is the greater side

we have

$c=\sqrt{20}\ units$

$a=\sqrt{17}\ units$

$b=\sqrt{13}\ units$

substitute

$c^{2}= (\sqrt{20})^{2}=20$

$a^{2}+b^{2}=(\sqrt{17})^{2}+(\sqrt{13})^{2}=30$

therefore

$c^{2}< a^{2}+b^{2}$

Is an acute triangle

6 0

3 years ago

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The local Tupperware dealers earned the following commissions last month. What was the mean commission earned? Round your answe

kirza4 [7]

Answer:

B. $ 3094.01

Step-by-step explanation:

Given observations are,

$2894.21, $1777.15, $2144.77, $4096.37, $4046.29, $1786.37, $3296.69, $4086.27, $2784.22

Number of observations = 10,

Sum of the observations = 2894.21+1777.15+2144.77+4096.37+4046.29+1786.37+3296.69+4086.27+2784.22+4027.79 = 30940.13,

Hence,

$Mean = \frac{\text{Sum of observations}}{\text{Number of observation}}$

$=\frac{30940.13}{10}$

$=3094.013$

$\approx 3094.01$

Option 'B' is correct.

5 0

3 years ago