Line f has a slope of –3 8 . Line g is parallel to line f . What is the slope of line g ?
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Answer:
Step-by-step explanation:
Taking 
and differentiating both sides with respect to 
yields
![\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B3x%5E2%2By%5E2%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B7%5Cbigg%5D%5Cimplies%206x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%3D0)
Solving for the first derivative, we have
Differentiating again gives
![\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B6x%2B2y%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cbigg%5B0%5Cbigg%5D%5Cimplies%206%2B2%5Cleft%28%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dx%7D%5Cright%29%5E2%2B2y%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D0)
Solving for the second derivative, we have
Now, when
and 
, we have
Solving for the first derivative, we have
Differentiating again gives
Solving for the second derivative, we have
Now, when
By graphing the points, The best mode of the data will be the quadratic function
There is 5 steps to find the quadratic function that models the data.
First step ⇒ Plot the data pairs (x, y) in a coordinate plane.
which are the blue circles in the attached figure
Second step ⇒ Draw the parabola you think best fits the data.
Which is the red function in the attached figure.
Third step ⇒ Estimate the coordinates of three points on the
parabola, which are (-1, 0), (2, -3), and (5, 12).
Fourth step ⇒ Substitute the coordinates of the points into the model
y = ax² + bx + c
to obtain a system of three linear equations.
a - b + c = 0 ---------(1)
4a + 2 b + c = -3 ---------(2)
25a + 5 b + c = 12 ---------(3)
Fifth step ⇒ Solve the linear system.
By using the calculator
a = 1 , b = -2 , c = -3
So, the quadratic model for the data is ⇒ y = x² - 2x - 3
There is 5 steps to find the quadratic function that models the data.
First step ⇒ Plot the data pairs (x, y) in a coordinate plane.
which are the blue circles in the attached figure
Second step ⇒ Draw the parabola you think best fits the data.
Which is the red function in the attached figure.
Third step ⇒ Estimate the coordinates of three points on the
parabola, which are (-1, 0), (2, -3), and (5, 12).
Fourth step ⇒ Substitute the coordinates of the points into the model
y = ax² + bx + c
to obtain a system of three linear equations.
a - b + c = 0 ---------(1)
4a + 2 b + c = -3 ---------(2)
25a + 5 b + c = 12 ---------(3)
Fifth step ⇒ Solve the linear system.
By using the calculator
a = 1 , b = -2 , c = -3
So, the quadratic model for the data is ⇒ y = x² - 2x - 3