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rosijanka [135]
3 years ago
13

Solve. -7x+1-10x^2=0

Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Answer:

-7x+1-10x^2=0

-10x^2-7x+1=0

quadratic\:equation:- ax^2+bx+c=0

solutions:-\\\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

For \\A=-10\\B=-7\\C=1

x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\left(-10\right)\cdot \:1}}{2\left(-10\right)}

\sqrt{\left(-7\right)^2-4\left(-10\right)\cdot \:1}=\sqrt{89}

x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{89}}{2\left(-10\right)}

x_1=\frac{-\left(-7\right)+\sqrt{89}}{2\left(-10\right)},\:x_2=\frac{-\left(-7\right)-\sqrt{89}}{2\left(-10\right)}

\frac{-\left(-7\right)+\sqrt{89}}{2\left(-10\right)}=-\frac{7+\sqrt{89}}{20}

\frac{-\left(-7\right)-\sqrt{89}}{2\left(-10\right)}=\frac{\sqrt{89}-7}{20}

x=\frac{\sqrt{89}-7}{20}

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