Question

Solve. -7x+1-10x^2=0

Answer 1

Answer:

$-7x+1-10x^2=0$

$-10x^2-7x+1=0$

$quadratic\:equation:-$ $ax^2+bx+c=0$

$solutions:-\\\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$For \\A=-10\\B=-7\\C=1$

$x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{\left(-7\right)^2-4\left(-10\right)\cdot \:1}}{2\left(-10\right)}$

$\sqrt{\left(-7\right)^2-4\left(-10\right)\cdot \:1}=\sqrt{89}$

$x_{1,\:2}=\frac{-\left(-7\right)\pm \sqrt{89}}{2\left(-10\right)}$

$x_1=\frac{-\left(-7\right)+\sqrt{89}}{2\left(-10\right)},\:x_2=\frac{-\left(-7\right)-\sqrt{89}}{2\left(-10\right)}$

$\frac{-\left(-7\right)+\sqrt{89}}{2\left(-10\right)}=-\frac{7+\sqrt{89}}{20}$

$\frac{-\left(-7\right)-\sqrt{89}}{2\left(-10\right)}=\frac{\sqrt{89}-7}{20}$

$x=\frac{\sqrt{89}-7}{20}$

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