The graph of is a horizontal line. So the area under
on [0, 8] is equal to the area of a rectangle with length 8 and height 2, or 16.
The graph of is the upper half of a circle with radius
. It's symmetric about
, so on the interval [0, 8], we're considering a quarter of the circle. The area of such a sector is
.
Then use the fact that the definite integral is distributive over sums, meaning
Given equation is y=3x+3 and
Let's simplify the 2nd equation before we can start graph so that calculation will be easy
multiply both sides by 3 to cancel out fractions
y=3x+3
which is exactly same as the first equation so graph of both will be exactly same and solution will be infinitely many solutions.
y=3x+3 has y-intercept 3 so first point will be (0,3). Slope is 3 so rise 3 unit up then 1 right and graph the new point.
