All categories

3 years ago

2.3 x 10^4 x 6.7 x 10^3 divide by 5 x 10-^8

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

4 0

Answer:

0.3082

Step-by-step explanation:

You might be interested in

Compare the functions below: Which function has the smallest minimum?

anzhelika [568]

Answer:

D. All three functions have the same minimum value

Step-by-step explanation:

f(x) = -3 sin (x-pi) +2

Sin has a minimum value of -1, but since it is multiplied by a negative, we want its maximum value

sin has a maximum of 1

f (min) = -3(1) +2 = -1

g(x) has a minimum at x =3

g(minimum) = -1

h(x) = (x+7)^2 -1

The smallest a squared value can be is zero

= 0 -1

h(min) =-1

5 0

3 years ago

Simplify: −√16x^2 , when x<0

Savatey [412]

Answer:

$-4|x|$

Step-by-step explanation:

To simplify :

$-\sqrt{16x^2}$ , when $x$

In order to simplify the given expression we will take the square root of the term inside the root.

The term in the square root are perfect squares (square of an integer), so, we can write them in square of the numbers.

⇒ $-\sqrt{(\pm4x)^2}$ [As $(\pm4x)^2=16x^2$ ]

On taking square root the square gets removed. So, we have,

⇒ $-(\pm4x)$

⇒ $-4|x|$

Since $x$ , so the value would be negative.

So, simplified answer is

$-4|x|$ (Answer)

3 0

3 years ago

Given right triangle ABC with altitude BD draw to hypotenuse AC. If AD=13 and DC=33,what is the length of BD in simplest radical

denis23 [38]

Answer:

8.06

Step-by-step explanation:

I used my brain and paper. I don't want to have to explain it anymore sorry but yes I think that is the right answer.

3 0

3 years ago

If tan theta =12/5 and cos theta < 0, what is sin theta ?

xenn [34]

If tan theta =12/5 and cos theta < 0, then sin theta is -12/13. The correct answer between all the choices given is the last choice or letter E. I am hoping that this answer has satisfied your query about and it will be able to help you.

8 0

3 years ago

A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s

jasenka [17]

Answer:

The minimum score of those who received C's is 67.39.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 73, \sigma = 11$