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3 years ago

How does writing equivalent equations help you solve a system of equations?

1 answer:

3 0

Writing equivalent equations help you solve system of equations because it sets it up for being broken down part by part.

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What does impeach mean?

ziro4ka [17]

Answer:

a. to accuse a public official, before an appropriate tribunal. of misconduct in office

6 0

2 years ago

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. Hint: the

Julli [10]

Answer:

Use the given degree of confidence and sample data to construct a confidence interval for the population proportion p. 16)n = 182, x = 135; 95 percent

✓ 16)n = 182, x = 135; 95 percent sample proportion: p-hat = 135/182 = 0.74 E = 1.96*sqrt[0.74*0.26/182] = 0.0637 95% CI: 0.74-0.0637 < p < …

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3 years ago

Use the Midpoint Rule with n = 5 to estimate the volume V obtained by rotating about the y-axis the region under the curve y = 1

velikii [3]

Using the shell method, the volume is given exactly by the definite integral,

$2\pi\displaystyle\int_0^1x(1+9x^3)\,\mathrm dx$

Splitting up the interval [0, 1] into 5 subintervals gives the partition,

[0, 1/5], [1/5, 2/5], [2/5, 3/5], [3/5, 4/5], [4/5, 5]

with left and right endpoints, respectively, for the $i$ -th subinterval

$\ell_i=\dfrac{i-1}5$

$r_i=\dfrac i5$

where $1\le i\le5$ . The midpoint of each subinterval is

$m_i=\dfrac{\ell_i+r_i}2=\dfrac{2i-1}{10}$

Then the Riemann sum approximating the integral above is

$2\pi\displaystyle\sum_{i=1}^5m_i(1+9{m_i}^3)\frac{1-0}5$

$\dfrac{2\pi}5\displaystyle\sum_{i=1}^5\left(\frac{2i-1}{10}+9\left(\frac{2i-1}{10}\right)^4\right)$

$\dfrac{2\pi}{5\cdot10^4}\displaystyle\sum_{i=1}^5\left(16i^4-32i^3+24i^2+1992i-999\right)=\frac{112,021\pi}{25,000}\approx\boxed{14.08}$

(compare to the actual value of the integral of about 14.45)

3 0

3 years ago

Can someone help me plz

lukranit [14]

The answer is area= 113.05 Circumference= 37.68

8 0

3 years ago

How do you determine if a relation is quadratic by calculation differences, analyzing a graph, examining the degree in an equati

Kryger [21]

1) We can determine by the table of values whether a function is a quadratic one by considering this example:

x | y 1st difference 2nd difference

0 0 3 -0 = 3 7-3 = 4

1 3 10 -3 = 7 11 -7 = 4

2 10 21 -10 =11 15 -11 = 4

3 21 36-21 = 15 19-5 = 4

4 36 55-36= 19

5 55

2) Let's subtract the values of y this way:

3 -0 = 3

10 -3 = 7

21 -10 = 11

36 -21 = 15

55 -36 = 19

Now let's subtract the differences we've just found:

7 -3 = 4

11-7 = 4

15-11 = 4

19-15 = 4

So, if the "second difference" is constant (same result) then it means we have a quadratic function just by analyzing the table.

3) Hence, we can determine if this is a quadratic relation calculating the second difference of the y-values if the second difference yields the same value. The graph must be a parabola and the highest coefficient must be 2

4 0

1 year ago