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labwork [276]
3 years ago
12

Hi!!!Calcula los divisores de cada número :8, 12 ,24 , 25 , 28, please . _ .​

Mathematics
1 answer:
Kamila [148]3 years ago
6 0
I think that it’s 23
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Use long division to determine the quotient of the polynomials. (x3 – 7x – 6) ÷ (x – 4) Which of the following options best desc
Lelechka [254]

Answer:

The correct option is c.

Step-by-step explanation:

The quotient of the polynomials is

\frac{(x^3-7x-6)}{x-4}

We need to find the remainder by using long division method.

The dividend of the given expression is

Dividend=x^3-7x-6

Divisor=x-4

The long division method is shown below.

\frac{(x^3-7x-6)}{x-4}=(x^2+4x+9)+\frac{30}{x-4}

From the below attachment it is clear that the quotient has a remainder of 30. Therefore, the divisor is not factor of the dividend.

Therefore the correct option is c.

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3 years ago
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ivanzaharov [21]

Step-by-step explanation:

The median is the middle number is an ordered set of data. In a frequency table, the observations are already arranged in an ascending order. We can obtain the median by looking for the value in the middle position. If there is an odd number of observations, the median is the middle number

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2 years ago
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andrew-mc [135]

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Step-by-step explanation:

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2 years ago
Write the ratio as a fraction in simplest form.
vitfil [10]

Answer:

Part 1) \frac{5}{2}  or  5:2

Part 2) \frac{8}{1}  or  8:1

Step-by-step explanation:

Write the ratio as a fraction in simplest form

Part 1) 15 girls to 6 boys

we know that

To find out the ratio, divide the number of girls by the number of boys

so

\frac{15}{6}

Simplify

Divide by 3 both numerator and denominator

\frac{5}{2}\ \frac{girls}{boys}

Part 2) 24 plays for 3 teams

we know that

To find out the ratio, divide the number of plays by the number of teams

so

\frac{24}{3}

Simplify

Divide by 3 both numerator and denominator

\frac{8}{1}\ \frac{plays}{team}

5 0
3 years ago
Let U = {q, r, s, t, u, v, w, x, y, z} A = {q, s, u, w, y} B = {q, s, y, z} C = {v, w, x, y, z}. List the elements in the set: A
gtnhenbr [62]

Answer:

A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}

Step-by-step explanation:

Given: \text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}, \text{A}=\left \{\text{q, s, u, w, y} \right \}, \text{B}=\left \{\text{q, s, y, z} \right \},

\text{C}=\left \{\text{v, w, x, y, z} \right \}.

To find: The elements in the set A \cup C.

Solution:

We have,

\text{U}=\left \{\text{q, r, s, t, u, v, w, x, y, z} \right \}

\text{A}=\left \{\text{q, s, u, w, y} \right \}

\text{B}=\left \{\text{q, s, y, z} \right \}

\text{C}=\left \{\text{v, w, x, y, z} \right \}

Now, A \cup C will contain all the elements in the set A and all the elements in set C.

So, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

Hence, A \cup C=\left \{  \text{q, s, u, v, w, x, y, z} \right \}.

7 0
2 years ago
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