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ale4655 [162]
3 years ago
9

Two consecutive whole numbers such that the sum of their squares is 13

Mathematics
1 answer:
valina [46]3 years ago
5 0
The square root of 169 is 13 and 170 is 13.03
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| 3х – 9| = 24<br> ??????????????????????????????????
Nadya [2.5K]

Answer:

x= 11

Step-by-step explanation:

3x= 24+9

3x= 33

x= 33/3

x= 11

hope it helps ,pls mark me as brainliest

5 0
3 years ago
Read 2 more answers
Can someone answer this for me pls I need help rly bad
grigory [225]

Answer:

the answer is y= 2/1x + 10

5 0
3 years ago
Find the equation of the line which passes through the point (-4,12) and is perpendicular to the given line. Express your answer
Vika [28.1K]

Answer:

y = 1/7x + 88/7

Step-by-step explanation:

y = mx +b

since it is perpendicular you have to get the negative reciprocal of the slope which is 1/7

y = 1/7x + b then you would plug in your points

12 = 1/7(-4) + b and then solve for b

12 = -4/7 + b

+ 4/7

88/7 = b

y = 1/7x + 88/7

8 0
3 years ago
Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

2x+3y=3 now +3y-3y=0

3x=-12+3

3x=-9

x=-3

plug in the first equation

-3-3y=-12

-3y=-12+3

-3y=-9

y=3

4 0
2 years ago
Solve Highschool Pre cal
Bezzdna [24]

Option C:

\ln 64 y^{2}

Solution:

Given expression: 2 ln 8 + 2 ln y

Applying log rule a \log b=\log b^{a}  in the above expression.  

⇒ 2 \ln 8+2 \ln y=\ln 8^{2}+\ln y^{2}

Applying log rule \log a+\log b=\log (a b) in the above expression.

⇒ \ln 8^{2}+\ln y^{2}=\ln \left(8^{2} y^{2}\right)

We know that 8^{2}=64

⇒ \ln \left(8^{2} y^{2}\right)=\ln 64 y^{2}

Hence, the expression in single natural logarithm is \ln 64 y^{2}.

6 0
3 years ago
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