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3 years ago

10x^3 - 25x^2 + 20 How to factor this

Mathematics

1 answer:

patriot [66]3 years ago

5 0

5(2x^2-x-2)(x-2)

Step-by-step

Answer: $5(\frac{10x^3}{5}+\frac{-25x^2}{5}+\frac{20}{5}) \\\\5(2x^3-5x^2+4)\\\\5(2x^2-x-2)(x-2)$

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What number is missing from the data set if the mean is 16? 14 12 19 X

Pie

Answer:

your numbers would be 14 12 19 19. Mean is the average. add the 4 numbers and divide by 4

Step-by-step explanation:

5 0

3 years ago

Slope intercept is what they're looking for

antiseptic1488 [7]

Super easy

y=mx+b
m=slope
b=yinterept

yintercept=4
slope=-3
y=-3x+4

4 0

3 years ago

The time required for the first stage of an assembly line is normally distributed with a mean of 28 minutes and variance of 5 mi

RoseWind [281]

<span>The mean for both processes is 28+17 = 45 minutes.
The variance is additive, so the total variance is 5+4 = 9. The standard deviation is the square root of variance, which is 3 minutes.
Then the z-score associated with a time of x = 50 minutes is:
z = (x - mean)/SD = (50 - 45)/3 = 1.67
From a z-table, the probability that (z > 1.67) is 0.0475.
</span>

7 0

3 years ago

LMNO is a parallelogram, with and . Which statements are true about parallelogram LMNO? Select three options.

Soloha48 [4]

In the parallelogram, m∠M is equal to m∠O, and the sum of m∠M and

m∠N is 180°.

Response:

The true statements are;

<u>x = 11°</u>

<u>m∠N = 59°</u>

<u>m∠O = 121°</u>

<h3>Which property of parallelogram are used to find the true statements?</h3>

The possible drawing of the parallelogram LMNO created with MS Visio is attached.

From the drawing, we have;

m∠M = 11·x

m∠N = 6·x - 7

The properties of a parallelogram are;

Opposite angles are equal.

Adjacent angles are supplementary

Which gives;

11·x + 6·x - 7 = 180°

17·x = (180 + 7)° = 187°

$x = \mathbf{\dfrac{187^{\circ}}{17} }= 11^{\circ}$

m∠M = 11 × 11° = 121° = m∠O

m∠N = 6 × 11° - 7 = 59° = m∠L

Therefore;

The statements that are true are;

x = 11°

m∠N = 59°

m∠O = 121°

Learn more about the properties of a parallelogram here:

brainly.com/question/7697302

7 0

2 years ago

You decide to enter in a rowing competition. To train, you go to the boat house and begin rolling down stream. You row for the s

fredd [130]

Answer:

Time spent rowing down stream $=100\ seconds$

Speed of boat in still water $=14\ ms^{-1}$

Step-by-step explanation:

Let speed of boat in still water be $= x\ ms^{-1}$

Speed of current $= 10\ ms^{-1}$

Speed of boat down stream = $\textrm{Speed of boat in still water +Speed of current}= (x+10)\ ms^{-1}$

Distance rowed down stream = 2400 m

Time spent rowing down stream = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$ = $\frac{Distance}{Speed}=\frac{2400}{x+10}\ s$

Speed of boat up stream = $\textrm{Speed of boat in still water -Speed of current}= (x-10)\ ms^{-1}$

Distance rowed up stream = $\frac{1}{6} \textrm{ of distance rowed downstream}=\frac{1}{6}\times 2400 = 400\ m$

Time spent rowing up stream = $\frac{Distance}{Speed}=\frac{400}{x-10}\ s$

We know that,

$\textrm{Time spent rowing down stream =Time spent rowing up stream}$

So,

$\frac{2400}{x+10}=\frac{400}{x-10}$

Cross multiplying

$2400(x-10)=400(x+10)$

Dividing both sides by $400$

$\frac{2400(x-10)}{400}=\frac{400(x+10)}{400}$

$6(x-10)=x+10$

$6x-60=x+10$

Adding 60 to both sides.

$6x-60+60=x+10+60$

$6x=x+70$

Subtracting both sides by $x$

$6x-x=x+70-x$

$5x=70$

Dividing both sides by 5.

$\frac{5x}{5}=\frac{70}{5}$

∴ $x=14$

Speed of boat in still water $=14\ ms^-1$

Time spent rowing down stream = $\frac{2400}{14+10}=\frac{2400}{24}=100\ s$

3 0

3 years ago