<h3>
Answer: Max height = 455.6 feet</h3>
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Explanation:
The general equation
y = ax^2 + bx + c
has the vertex (h,k) such that
h = -b/(2a)
In this case, a = -16 and b = 147. This means,
h = -b/(2a)
h = -147/(2*(-16))
h = 4.59375
The x coordinate of the vertex is x = 4.59375
Plug this into the original equation to find the y coordinate of the vertex.
y = -16x^2+147x+118
y = -16(4.59375)^2+147(4.59375)+118
y = 455.640625
The vertex is located at (h,k) = (4.59375, 455.640625)
The max height of the rocket occurs at the vertex point. Therefore, the max height is y = 455.640625 feet which rounds to y = 455.6 feet
8*4-4/2+1
32-4/2+1
32-2+1
=31 answer
So, the answer to this question is 31
√((x^6)/(y^4))
x^6 indicates x to the sixth power, the same goes for y^4.
Circumference = 2πr
3π=2πr
r=3π÷2π
r=3/2
area of a circle= πr²
=π×(3/2)²
=2.25π
Answer:
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Step-by-step explanation:
