Answer:
A. slope = -2; point = (8, -3)
Step-by-step explanation:
Compare to the point-slope form for slope m and point (h, k).
y -k = m(x -h)
You see that k = -3, m = -2, h = 8, so ...
- the slope is -2
- the point is (h, k) = (8, -3)
Answer:
The 80% confidence interval for the the population mean nitrate concentration is (0.144, 0.186).
Critical value t=1.318
Step-by-step explanation:
We have to calculate a 80% confidence interval for the mean.
The population standard deviation is not known, so we have to estimate it from the sample standard deviation and use a t-students distribution to calculate the critical value.
The sample mean is M=0.165.
The sample size is N=25.
When σ is not known, s divided by the square root of N is used as an estimate of σM:
![s_M=\dfrac{s}{\sqrt{N}}=\dfrac{0.078}{\sqrt{25}}=\dfrac{0.078}{5}=0.016](https://tex.z-dn.net/?f=s_M%3D%5Cdfrac%7Bs%7D%7B%5Csqrt%7BN%7D%7D%3D%5Cdfrac%7B0.078%7D%7B%5Csqrt%7B25%7D%7D%3D%5Cdfrac%7B0.078%7D%7B5%7D%3D0.016)
The degrees of freedom for this sample size are:
![df=n-1=25-1=24](https://tex.z-dn.net/?f=df%3Dn-1%3D25-1%3D24)
The t-value for a 80% confidence interval and 24 degrees of freedom is t=1.318.
The margin of error (MOE) can be calculated as:
Then, the lower and upper bounds of the confidence interval are:
![LL=M-t \cdot s_M = 0.165-0.021=0.144\\\\UL=M+t \cdot s_M = 0.165+0.021=0.186](https://tex.z-dn.net/?f=LL%3DM-t%20%5Ccdot%20s_M%20%3D%200.165-0.021%3D0.144%5C%5C%5C%5CUL%3DM%2Bt%20%5Ccdot%20s_M%20%3D%200.165%2B0.021%3D0.186)
The 80% confidence interval for the population mean nitrate concentration is (0.144, 0.186).
Is there a way you can do this in English like write it in English?
Answer:
Event D
Step-by-step explanation:
Complementary events are those events that are opposites of each other. i.e. in this case the complementary event for choosing a green marble is not choosing a green. It has nothing to do with choosing or not choosing marbles of colors other than green.