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spayn [35]
3 years ago
10

How would you describe the correlation in the data? Explain your reasoning. (2 points).

Mathematics
1 answer:
ANTONII [103]3 years ago
5 0

Answer:

Hi

Step-by-step What is a linear function in the form y= mx + b for the line passing through (4.5, -4.25) with y-intercept 2.5 yup help pleade

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The school's lemonade is $10\%$ lemon juice by volume, and the rest is sugar water. how many liters of lemon juice must be added
kondor19780726 [428]
The percentage of lemon in the juice is 10%
The percentage of water sugar is (100-10)=90%
The quantity of lemon in 20 liters of sugar water will be:
amount=(percentage of lemon)/(percentage of sugar water)×(amount of sugar water)
=10/90×20
=2 2/9 liters 
3 0
3 years ago
Read 2 more answers
Find the Mean of the following set of data. (Round to the
Vikentia [17]

Answer:

2.75

Step-by-step explanation:

to get the mean all you have to is add all the numbers up then divide by how numbers there are. so 3e is what u get when u add them up then divide by 12 and u get 2.75

3 0
3 years ago
When 142 is added to a number, the result is 64 more than 3 times the number. Find
dmitriy555 [2]
X+142 =3x+64

subtract x from each side

142 = 2x+64

subtract 64 from each side

142-64 = 2x

78=2x

divide by 2

78/2 = x

x=39

The number is 39
8 0
3 years ago
What is the nearest integer: 4.18/0.68
liubo4ka [24]
I am thinking ,4 and 70 
4 0
4 years ago
What are the real and complex solutions of the polynomial equation? x^4-41x^2=-400. *work needed*
pickupchik [31]
<h3>Answer: x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>

Step-by-step explanation:

Given the polynomial equation x^4-41x^2=-400.

Adding 400 on both sides to get rid 400 from right side and set 0 on right side, we get

x^4-41x^2+400=-400+400.

x^4-41x^2+400=0.

Factoring by product sum rule.

We need product of 400 and sum upto -41.

We can see that 400 = -25 × -16 = 400 and -25-16 = -41.

Therefore,

x^4-25x^2-16x^2+400=0

Making it into two groups, we get

(x^4-25x^2)+(-16x^2+400)=0

Factoring out GCF of each group, we get

x^2(x^2-25)-16(x^2-25)=0

(x^2-25)(x^2-16) =0

Factoring out  (x^2-25) and (x^2-16) separately by difference of the squares identity a^2-b^2=(a-b)(a+b), we get

(x^2-25) = x^2-5^2= (x-5)(x+5) and

x^2-16 = x^2-4^2 =(x-4)(x+4).

Therefore,

(x-5)(x+5)(x-4)(x+4) =0

Applying zero product rule,

x-5=0

x+5=0

x-4=0 and

x+4=0.

Therefore,

<h3>x = -5, -4, 4 and 5.</h3><h3>All four zeros are real solutions.</h3>
6 0
3 years ago
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