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Law Incorporation [45]
3 years ago
8

What are the values of a,b,c,and d

Mathematics
1 answer:
levacccp [35]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

Given that l_{1} and l_{2} are parallel lines then

a = 35 ( alternate angle )

The sum of the angles in a triangle = 180°, thus

b = 180 - (90 + a) = 180 - (90 + 35) = 180 - 125 = 55

b and c form a straight angle, thus

c = 180 - b = 180 - 55 = 125

d = 55 ( alternate to b )

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3 years ago
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Jade used candle molds, as shown, to make candles that were perfect cylinders and spheres:
Fittoniya [83]

Answer:

The difference in the amount of wax needed is 84.78 in³ (84.78 cubic inches)

Step-by-step explanation:

Given

<em>Cylinder</em>

Radius = 3 inches

Height = 7 inches

<em>Sphere</em>

Radius = 3 inches

Required

The difference in the amount of wax needed to make a candle from each of these molds

The quantity or amount required to make a wax of candle from each molds can be calculated by getting the volume of both molds

The volume of a cylinder is calculated using

<em>V₁ = πr²h</em>

where r and h are the radius and the height of the cylinder, respectively.

r = 3 in and h = 7 in

The volume of a sphere is calculated using

V_{2} = \frac{4}{3}\pi r^3

where r is the radius of the sphere

r = 3 in

Calculating V₁

V₁ = πr²h

V₁ = π * 3² * 7

V₁ = π * 9 * 7

V₁ = π * 63

V₁ = 63π

Calculating V₂

V_{2} = \frac{4}{3}\pi r^3

V_{2} = \frac{4}{3} * \pi * 3^3

V_{2} = \frac{4}{3} * \pi * 27

V_{2} = \frac{108}{3} * \pi

V₂ = 36π

Having calculated the volume of each molds, the difference in the amount of wax needed can then be calculated.

Difference = V₁ - V₂

Substituting 63π for V₁ and 36π for V₂

Difference = 63π - 36π

Difference = 27π

<em>(Taking π = 3.14)</em>

Difference = 27 * 3.14

Difference = 84.78

Hence, difference in the amount of wax needed is 84.78 in³

8 0
3 years ago
Read 2 more answers
Draw a diagram in which segment AB intersects segment CD equals segment CB
Contact [7]
The <u>correct diagram</u> is attached.

Explanation:

Using technology (such as Geogebra), first construct a line segment.  Name the endpoints C and D.

Construct the perpendicular bisector of this segment.  Label the intersection point with CD as B, and create another point A above it.

Measure the distance from C to B and from B to D.  They will be the same.

Measure the distance from A to B.  If it is not the same as that from C to B, slide A along line AB until the distance is the same.

Using a compass and straightedge:

First construct segment CD, being sure to label the endpoints.

Set your compass a little more than halfway from C to D.  With your compass set on C, draw an arc above segment CD.

With your compass set on D (the same distance as before) draw an arc above segment CD to intersect your first arc.  Mark this intersection point as E.

Connect E to CD using a straightedge; mark the intersection point as B.

Set your compass the distance from C to B.  With your compass on B, mark an arc on EB.  Mark this intersection point as A.

AB will be the same distance as CB and BD.

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3 years ago
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I need help in partial fraction!! With simple explaination would be nice!
WITCHER [35]
\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}

The degree of the numerator (4) is larger than the degree of the denominator (3), so first you need to divide. (Added screenshot of long division procedure.)

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x-\dfrac{4x^2-17x+10}{x(x^2-3)}

Now the second term can be decomposed into partial fractions.

\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1}x+\dfrac{r_2x+r_3}{x^2-3}
\dfrac{4x^2-17x+10}{x(x^2-3)}=\dfrac{r_1(x^2-3)+x(r_2x+r_3)}{x(x^2-3)}
4x^2-17x+10=r_1(x^2-3)+x(r_2x+r_3)
4x^2-17x+10=(r_1+r_2)x^2+r_3x-3r_1
\implies\begin{cases}r_1+r_2=4\\r_3=-17\\-3r_1=10\end{cases}\implies r_1=-\dfrac{10}3,r_2=\dfrac{22}3,r_3=-17=-\dfrac{51}3
\implies\dfrac{4x^2-17x+10}{x(x^2-3)}=-\dfrac{10}{3x}+\dfrac{22x-51}{x^2-3}

So

\dfrac{x^4-7x^2+17x-10}{x(x^2-3)}=x+\dfrac{10}{3x}-\dfrac{22x-51}{x^2-3}

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3 years ago
Angela shared a cab with her friends. When they arrived at their destination, they evenly divided the $j fare among the 3 of the
igor_vitrenko [27]

Answer:

(j/3)+5

thats the answer

8 0
3 years ago
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