Get the x terms by themselves on one side and a constant on the other side of the equal sign...
4x^2-8x=1 make the leading coefficient equal to one...
x^2-2x=1/4 now halve the linear coefficient, -2 in this case, square it, and add that value to both sides of the equation...-2/2=-1, -1^2=1 so
x^2-2x+1=1+1/4
x^2-2x+1=5/4 now the left side is a perfect square...
(x-1)^2=5/4 take the square root of both sides...
x-1=±√(5/4) add 1 to both sides
x=1±√(5/4)
isosceles Acute
Step-by-step explanation:
I think I'm pretty sure that right sorry if I'm wrong
soo are these real math questions? I mean like do your teachers actually ask you these kind of questions or you are making all this up? because they seem to have no answers for them at all
I hope this is a joke tbh
By the pythagorean theorem the diagonal length will be:
d^2=x^2+y^2 and since this is a square x=y so
d^2=2x^2 and since d=15
225=2x^2
x^2=112.5
x=√112.5 yds
x≈10.6 yds (to nearest tenth of a yard)
