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Nataly_w [17]
3 years ago
7

Mass production usually uses an _______________ ____________ or production line technique.

Computers and Technology
1 answer:
Sidana [21]3 years ago
6 0
<span>The production of large quantities of a standardized article (often using assembly line techniques).</span>
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This program will store roster and rating information for a soccer team. Coaches rate players during tryouts to ensure a balance
aksik [14]

Answer:

import java.util.Scanner;

public class TeamRoster {

  public static void main(String[] args) {

     Scanner scan = new Scanner(System.in);

     int[][] players = new int[5][2];

     boolean keepAlive = true;

     char input;

     

     for (int i = 0; i < 5; i++) {

        System.out.println("Enter player " + (i+1) + "'s jersey number: ");

        players[i][0] = scan.nextInt();

        if( players[i][0] >= 0 && players[i][0] < 100 ) {

             System.out.println("Enter player number less than 100");

               System.out.println("Enter player " + (i+1) + "'s rating: ");

               players[i][1] = scan.nextInt();

               if ( players[i][1] >= 1 && players[i][1] <10 ) {

                     System.out.println();

               }    else {

                     System.out.println("Enter player " + (i+1) + "'s rating: ");

                     players[i][1] = scan.nextInt();

               }

     }

     }

     System.out.println();

     outputRoster(players, 0);

     

     while (keepAlive) {

        outputMenu();

        input = scan.next().charAt(0);

        if (input == 'q') {

           keepAlive = false;

           break;

        } else if (input == 'o') {

           outputRoster(players, 0);

        } else if (input == 'u') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           System.out.println("Enter a new rating for the player: ");

           int newRating = scan.nextInt();

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 players[l][1] = newRating;

              }

           }

        } else if (input == 'a') {

           System.out.println("Enter a rating: ");

           int rating = scan.nextInt();

           outputRoster(players, rating);

        } else if (input == 'r') {

           System.out.println("Enter a jersey number: ");

           int jerseyNum = scan.nextInt();

           boolean exists = true;

           for (int l = 0; l < 5; l++) {

              if (players[l][0] == jerseyNum) {

                 System.out.println("Enter a new jersey number: ");

                 players[l][0] = scan.nextInt();

                 System.out.println("Enter a rating for the new player: ");

                 players[l][1] = scan.nextInt();

              }

           }

           

        }

     }

     

     return;

  }

   

  public static void outputRoster(int[][] players, int min) {

     System.out.println(((min>0) ? ("ABOVE " + min) : ("ROSTER")));

     int item = 1;

     for (int[] player : players) {

        if (player[1] > min) {

           System.out.println("Player " + item + " -- Jersey number: " + player[0] + ", Rating: " + player[1]);

        }

        item++;

     }

     System.out.println();

  }

   

  public static void outputMenu() {

     System.out.println("MENU");

     System.out.println("u - Update player rating");

     System.out.println("a - Output players above a rating");

     System.out.println("r - Replace player");

     System.out.println("o - Output roster");

     System.out.println("q - Quit\n");

     System.out.println("Choose an option: ");  

  }

}

Explanation:

The program is written in Java.

It is a bit straightforward.

The Scanner module is declared and used to collect input from the user.

The program prompts the user for each player jersey then rating.

All five players details are collected.

The program shows the output of all the entries.

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2 years ago
Can you help me solve this challenging activity?
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Answer:

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Explanation:

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